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To produce 60 watts at 120 volts, you need 0.5 amps (Watts = Volts * Amps) At 120volts, a 240ohm resistor would produce 0.5 amps (Amps = Volts / Resistance) A 60 watt bulb will have a resistance of 240 ohms. Note that this is the resistance while the bulb is hot. You might measure a different resistance if you use an ohm meter because the filament is cold.
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If their is more bulbs in a circuit does the resistance increase?
Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).
Which 12 volt bulb will draw the most current when connected to a 12 volt battery?
The bulb with the lowest resistance. Current = Volts / Resistance
Why does the current in an electric circuit decrease when more bulbs are added?
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt light bulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt power source and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. In simpler words: If you double the bulbs, twice the current is drained from the battery
Four 2.0 v cells are connected in a series to a 12 resistance light bulb If the resulting current flow is 0.62A what is the internal resistance of each cell?
This looks like V=IR to meTransposing to R = V/I and assuming that's a 12 ohm bulbLet x be the unknown part of the circuit's resistance12 + x = 8 / 0.62, so12 + x = 12.9, thereforex = 0.9 ohms.x / 4 = 0.225 ohms
How much curretn is in a circuit that includes a 9- volt battery and bulb with a resistance of 12 ohms?
Current, I is equal to V (voltage) divided by R (resistance); Hence: I=V/R = 9V/200 ohms: I = 0.045 Amps, or 45ma (milliamps).
