To produce 60 watts at 120 volts, you need 0.5 amps (Watts = Volts * Amps) At 120volts, a 240ohm resistor would produce 0.5 amps (Amps = Volts / Resistance) A 60 watt bulb will have a resistance of 240 ohms. Note that this is the resistance while the bulb is hot. You might measure a different resistance if you use an ohm meter because the filament is cold.
Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).
The bulb with the lowest resistance. Current = Volts / Resistance
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt light bulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt power source and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. In simpler words: If you double the bulbs, twice the current is drained from the battery
This looks like V=IR to meTransposing to R = V/I and assuming that's a 12 ohm bulbLet x be the unknown part of the circuit's resistance12 + x = 8 / 0.62, so12 + x = 12.9, thereforex = 0.9 ohms.x / 4 = 0.225 ohms
Current, I is equal to V (voltage) divided by R (resistance); Hence: I=V/R = 9V/200 ohms: I = 0.045 Amps, or 45ma (milliamps).
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
Yes. The resistance of a globe depends not only on the wattage of it but also on the voltage. A 12 V Globe would has a quarter the resistance of a 24 volt globe for the same wattage. (when alight)
Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).
If the two bulbs use the same technology the 100 w bulb is 10/6 times brighter than the 60 w. Incandescent bulbs give about 10-12 lumens per watt Halgogen gives about 15-18 lumens per watt CFL (low-energy) gives about 50 lumens per watt.
The current drawn by the 60-watt 12-volt light bulb is equal to the power divided by the voltage, so it would be 5 amps.
Yes, a 12 volt auto light bulb can work on 12 volt AC, but the light output might be slightly lower compared to when using DC. The bulb will still produce light, but it may flicker due to the alternating current.
Yes it it is a 12 volt DC light bulb. It will not operate a household 120 volt light bulb.
He invented the incandescent light bulb and it took him 12 years.
In theory the formula V = IR (I is current), 12/55 or approximately 0.2 ohms. But in reality the resistance probably will go to infinity, as that much current would almost certainly blow the filament. I doubt any 12 V bulb could dissipate 12*55 = 660 watts for any extended amount of time. But who knows...
Okay so I searched for 3 hours on Google and no answer so here it is: 40W - 110C; 60W 140C; 100W 136C; and 100W Flood (Red Green Yellow) 125C. Standard bulb, 117VAC, 60Hz, facing up (edison Base down, free air, 22C ambient, measured with K-type thermocouple, calibrated in last 12 months....
12 volts
it took Edison 15-17 years to make the light bulb