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To produce 60 watts at 120 volts, you need 0.5 amps (Watts = Volts * Amps) At 120volts, a 240ohm resistor would produce 0.5 amps (Amps = Volts / Resistance) A 60 watt bulb will have a resistance of 240 ohms. Note that this is the resistance while the bulb is hot. You might measure a different resistance if you use an ohm meter because the filament is cold.

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15y ago
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14y ago

P = 60W = V^2 / R

60 = 144/R

R = 2.4 ohms.

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14y ago

using the equation V=IR

we rearrange to make I=V/R

the V is 12 the R is 60 so

I=12/60

I= 0.2 Amps.

I is current, V is volts and R is resistance.

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12y ago

Ohm's Law

Voltage = Current x Resistance

120 /240 = .5

This is a 60 watt bulb.

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12y ago

Current = voltage/resistance = 12/4 = 3 amperes

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15y ago

I = E/R = 120/60 = 2 Amperes

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14y ago

2 amperes

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12y ago

3.2

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Q: What is the resistance in a 60W 12 V light bulb?
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Continue Learning about Engineering

If their is more bulbs in a circuit does the resistance increase?

Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).


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The bulb with the lowest resistance. Current = Volts / Resistance


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This looks like V=IR to meTransposing to R = V/I and assuming that's a 12 ohm bulbLet x be the unknown part of the circuit's resistance12 + x = 8 / 0.62, so12 + x = 12.9, thereforex = 0.9 ohms.x / 4 = 0.225 ohms


How much curretn is in a circuit that includes a 9- volt battery and bulb with a resistance of 12 ohms?

Current, I is equal to V (voltage) divided by R (resistance); Hence: I=V/R = 9V/200 ohms: I = 0.045 Amps, or 45ma (milliamps).

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