Your question shows the importance of using the correct symbols, because your symbols are incorrect and, therefore, your question is confusing.
So, are you asking how many milliwatts (mW) there are in a kilowatt (kW), or are you asking how many megawatts (MW) there are in a kilowatt(kW)?
Notice that the symbol for a watt is an upper-case W. The symbol for a milli is a lower-case m, and the symbol for a mega is an upper-case M.
If the former, then there are one-thousand milliwatts in a watt, and there are one-thousand watts in a kilowatt, so there must be one-million milliwatts in a kilowatt.
If the latter, then there are one-thousand kilowatts in a megawatt, so a megawatt must be one-thousandth of a megawatt in a kilowatt.
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With average usage it would supply about 25 houses. It could be assumed that some houses would draw more power than others at any moment, so the average would be about 3 to 4 kW.
The total kW load is only a guide to the solar panel capacity. Any energy generated by the solar panel will reduce the energy you draw from the grid, which leads directly to less CO2 output at the power plants. But the power plant is still needed for when there is a cloudy day. When it's cloudy the solar panel output is drastically reduced, although they still produce power, as the salesmen are keen to emphasize, but what they don't tell you is that the power output is reduced by about 95%. Also, in many countries, if your panels generate excess electricity you sell it back to the grid, so the capacity of the panels is not critical.
If they are at the same voltage, and the same kW, the only thing left that will influence the output amperage is the power factor the generator is running at.
Yes, you can use both, but watts is more useful; it provides the total amount of power the generator can output.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
The mechanical load of a motor determines the necessary output power rating of an electric motor. As mechanical loads are defined in terms of watts (or, in North America, horse power), then motor's output must be rated in watts, too.The so-called 'power' rating of a transformer is determined by the rated voltage and the rated current of its secondary winding. The product of these two quantities is the transformer's rated 'apparent power', expressed in volt amperes.Incidentally, the symbol for "kilowatts" is "kW", not"KW's"!