No, java does not support explicit operator overloading. You can use an operator only for its intended purpose. But the "+" operator is implicitly overloaded. It can be used to add two numbers as well as concatenate two strings. Apart from this operator all other operators can be used only for their specific purpose.
it cannot be operator overloaded.
The prefix increment operator is overloaded as operator++() while the postfix increment operator is overloaded as operator++(int).
The only "special" operators in C++ are those that cannot be overloaded. That is; the dot member operator (.), pointer to member operator (.*), ternary conditional operator (:?), scope resolution operator (::), sizeof() and typeof().
The ternary operator (known as the conditional operator in C++) cannot be overloaded because it is impossible to pass a test operand and two expression operands (either or both of which may be comma-separated) to a function. You can only pass values or references as arguments to a function. Even if it were possible, built-in functions and operators that rely on the conditional operator would likely break. Like all the other operators that cannot be overloaded (sizeof, typeid, ::, . and .*) the results must always be predictable because built-in operators and functions rely on them so heavily.
Yes. Any function can be overloaded. However you cannot override a static member function. Only instance members can be overridden.
it cannot be operator overloaded.
comma (,) is an example
conditional operator , size of operator , membership operator and scope resulation operator can not be overload in c++
The prefix increment operator is overloaded as operator++() while the postfix increment operator is overloaded as operator++(int).
1. Member-of operator (.) 2. Pointer-to-member-of operator (.*) 3. Ternary condition operator (?:) 4. Scope resolution operator (::) 5. sizeof operator 6. typeid operator
The only "special" operators in C++ are those that cannot be overloaded. That is; the dot member operator (.), pointer to member operator (.*), ternary conditional operator (:?), scope resolution operator (::), sizeof() and typeof().
The ternary operator (known as the conditional operator in C++) cannot be overloaded because it is impossible to pass a test operand and two expression operands (either or both of which may be comma-separated) to a function. You can only pass values or references as arguments to a function. Even if it were possible, built-in functions and operators that rely on the conditional operator would likely break. Like all the other operators that cannot be overloaded (sizeof, typeid, ::, . and .*) the results must always be predictable because built-in operators and functions rely on them so heavily.
No.
You cannot create any new operators in C++. You can only overload the existing ones (although some, such as sizeof, new and delete cannot be overloaded). The only way to create a new operator is to implement it as a standard function with a named identifier. For instance, sqrt() is the standard library function that provides the square root operator, for which no real operator exists.
Java does not support user defined operator overloading.The operator '+' is overloaded in Java and can be used for adding both numbers and Strings.
class travel {...travel &operator=( some type );... or ...travel operator=( some type );...};
any number of arguments