You will find your answer in a paper and experiment done at the University of Applied Sciences Jena in Germany. They (M. Schimmelpfening, K. Weber, F Kalb & K.-H. Feller) determined the expansion coefficients of 9 samples of parafin wax with regards to Congealing Point, Needle Penetration and if a crystal transformation had occurred. They included a fully refined macrocrystalline, an intermediate and a plastic microcrystalline. The coefficients range from the micro wax with the higher CP and Pen at .73 X10 (-3) to the 2 phase waxes at .89 x 10(-3) and intermediate at .75. Check out their paper on how they determined these, it's good. Google "Volume expansion of parafins from dip tube measurements"
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There are so many diffrent kinds of "wax" that the question needs to be more specific to answer it. In any case, I don't know, yet. I cam across this in the process of searching for waxes that are used in autonomous underwater vehicles, called "gliders."
Formula for the volume Expansion for a solid is αV=1VdVdT and Isotropic materials is αV=3αL.
Since most metals are isotropic, the cubical coefficient of expansion is three times the linear coefficient of expansion. The linear coefficient of expansion is obtained from measurement and tables for the specific material which are readily available.
dL/dT = αL*L, where L is the length of the steel, T is temperature, and αL is the linear thermal expansion coefficient which for steel is about 11.0 to 13.0. That is possibly the easiest differential equation in history: (1/L)dL = (αL)dT ln(L) = αLT L = eαLT
0.0000055
nickel