The formula for amps when kilowatts are stated is; kW x 1000/1.73 x Volts x pf.
10 x 1000/1.73 x 415 x .8 = 10000/574 = 17 amps.
The electrical code states that motor feeders have to be rated at 125% of the motors FLA (full load amps). 17 x 125% = 21 amps.
A #10 copper conductor with an insulation factor of 75 or 90 degrees C are both rated at 30 amps.
p= V*I*COS FIEE SAY COS PYE IS UNITY10*1000=230*I*1I= 10000/230I=43.4 AComment10 kW is the output power of the machine. You will need to know the machine's efficiency in order to determine its input power before applying the above equation.
To answer this question the voltage of the unit must be given.
If the generator is a 12 lead reconnectable, you can use something called a zig-zag connection.Check the link below. It is an installation manual for a Marathon generator. Zig-zag connections are shown on page 8. For a home, you would use the low zig-zag connection for 120/240V (in the US). One caveat: you can only load a zig-zag single-phase connected generator to a maximum of 66% of its rated load. So, a 15kW 3-phase generator would only provide 10kW single-phase power. If this doesn't quite make sense, hire a pro!IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS. If you do this work yourself, always turn off the power at the breaker box/fuse panel BEFORE you attempt to do any work AND always use a meter or voltage indicatorto insure the circuit is, in fact, de-energized.
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To calculate the phase current of a 10kW 3-phase motor, you can divide the total power (10kW) by the square root of 3 (approx. 1.732) and then divide that result by the line-to-line voltage. The formula is: Phase Current (Amps) = Power (W) / (√3 x Line-to-Line Voltage (V)).
To answer this question the full load amperage of the motor and what phase the motor is, should have been given. This answer uses the motor amperage give in the electrical code book and will be close for your purpose. A 6 HP is not a common size motor. 7.5 HP motor is 25.3 amps. Using a power factor of 90%. W = I x E x 1.73 x pf, W = 25.3 x 220 x 1.73 x .9 = 8666 watts. A 10kW three phase generator will probably start the motor if it is not under load when it starts. A 15 kw generator would be better. A single phase 7.5 HP motor draws 40 amps. W = I x E x pf = 40 x 220 x .9 = 7920. Again A 10kW single phase generator will probably start the motor if it is not under load when it starts. A 15 kw generator would be better.
The short answer is no. The long answer is no, not if you are using standard 100-120 volt or 220-240volts found in most (all?) countries The following is a simplified best case scenario, which incorrectly assumes a power factor of 1. Power = Volts * Amps Watts = Volts * AMPS (Actually VA = Volts * Amps, but VA=Watts in best case scenario) but 10kw > 240 * 32. David
10kw generators are available for purchase at Home Depot. They sell the Briggs & Stratton models which are known to be durable and dependable. These generators can get you through the worst of power outages.
Yes, it is generally safe to start an AC motor with an inverter that has a higher power rating. The inverter's capacity should exceed the motor's power requirements to ensure sufficient starting torque. However, it is important to ensure that the inverter is correctly configured and that the motor is compatible with the inverter's voltage and frequency output.
Since watts = volts times amps times 1.73 times power factor (for a three phase motor): W = E * I * 1.73 * PF Solving for I: I = W / (E * 1.73 * PF) Lets say your motor has a PF of 0.85: I = 10000 / (415 * 1.73 * 0.85) I = 16.39A If this is for your homework (I hope not) and PF is not given, then you will substitute 1.0 for the PF and, of course, arrive at a different answer!
p= V*I*COS FIEE SAY COS PYE IS UNITY10*1000=230*I*1I= 10000/230I=43.4 AComment10 kW is the output power of the machine. You will need to know the machine's efficiency in order to determine its input power before applying the above equation.
To answer this question the voltage of the unit must be given.
10kW = 10,000 watts
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
"10kW on ring" likely refers to a 10-kilowatt power supply for a ring or jewelry making equipment. This term indicates the amount of power the ring or jewelry making process requires to operate efficiently. It is important to ensure that the power supply meets the specific requirements to avoid damaging the equipment or compromising the quality of the jewelry produced.
yes