The volt ampere (V.A) is the unit of measurement of apparent power.
Apparent power is the vector sum of a circuit's true power and reactive power.
A kV.A (not 'KVA') is the symbol for kilovolt ampere, whereas MV.A (not'MVA') is the symbol for megavolt ampere. So the latter is one-thousand times greater than the former!
VA or KVA or MVA
You can't determine the output voltage of a transformer by knowing kva. Transformers will be marked as to input and output voltages. Some will have multiple input and output voltages. The output voltage depends on the ratio of coil turns between input and output.
Do you mean 'megavolt ampere' (MV.A) or 'millivolt ampere' (mV.A)? By using the incorrect symbol ('mva'), this is not clear.To determine the apparent power, in volt amperes, you divide the true power, in watts, by the power factor of the load. One volt ampere is one-millionth of a megavolt ampere ('MV.A' -not 'mva') -assuming you don't mean 'millivolt ampere' ('mV.A')!
KV, kilovolts, or kilojoules per coulomb is not the same thing as KVA, kilovoltamperes, or kilojoules per second, and no direct comparison exists. Please restate the question.
There are two concerns here regarding loading on transformers of this size. First is the difference between MVA and MW. MW is just real power -- watts. MVA is total power which includes real power (MW) and reactive power (MVAR).--- http://en.allexperts.com/q/Electric-Power-Utilities-2405/operation-limit-oof-power.htm
VA or KVA or MVA
The power in a 15 MVA (15000 KVA) transformer depends on the power factor. You did not specify the power factor, so I will assume a power factor of 0.92. Simply multiply MVA by PF and you get 13.8 MW.
The 3 kVA transformer will weigh double the 1.5 kVA transformer.
A 132 kV substation is normally called a grid substation. It would normally use two or more 132/33 kV transformers rated at 90 MVA, or two or more 132/11 kV transformers rated at 30 MVA.
You can't determine the output voltage of a transformer by knowing kva. Transformers will be marked as to input and output voltages. Some will have multiple input and output voltages. The output voltage depends on the ratio of coil turns between input and output.
Do you mean 'megavolt ampere' (MV.A) or 'millivolt ampere' (mV.A)? By using the incorrect symbol ('mva'), this is not clear.To determine the apparent power, in volt amperes, you divide the true power, in watts, by the power factor of the load. One volt ampere is one-millionth of a megavolt ampere ('MV.A' -not 'mva') -assuming you don't mean 'millivolt ampere' ('mV.A')!
KV, kilovolts, or kilojoules per coulomb is not the same thing as KVA, kilovoltamperes, or kilojoules per second, and no direct comparison exists. Please restate the question.
MVA we are so tight MVA not supposed to fight MVA we are so cool MVA we act like fools. MVA stands for Martina Victoria and Anaya. Bianca not included
There are two concerns here regarding loading on transformers of this size. First is the difference between MVA and MW. MW is just real power -- watts. MVA is total power which includes real power (MW) and reactive power (MVAR).--- http://en.allexperts.com/q/Electric-Power-Utilities-2405/operation-limit-oof-power.htm
For normal power factors (pf=80%), you have 0.8 kW for every kva. In general however, kW = pf x kVA. Where pf is the power factor, it is the cosine of the angular difference between the voltage and the current of a circuit in alternating current circuits.
MVA is the apparent power. MVA=( MW+ MVAr)1/2
MVA is the aparant power.