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The bit addressable memory in 8051 is compose from 210 bits:

- bit address space: 20H - 2FH bytes RAM = 00H - 7FH bits address;

- SFR registers;

The following addresses are NOT bit addressable, only 1-byte addressable:

- 32 bytes RAM from 00H to 1FH (R0 - R7 registers in all four banks);

- 80 bytes RAM general user from 30H to 7FH.

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Q: What is bit addressable memory in microcontroller 8051?
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Which are internal bit addressable RAM locations of 8051?

The 16 bytes (128 bits) at internal RAM locations 0x20-0x2F are bit-addressable.


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Of the 128-byte internal RAM of the 8051, only 16 bytes are bit-addressable. The rest must be accessed in byte format. The bit-addressable RAM locations are 20H to 2FH.


Bit addressable registers in 8051?

just a note: Clarify your question Bit-addressable registers are registers that its bits can be modified individually. that means if you have register named "ACC" that is bit addressable , you can change its bits (D0 -D7) individually by special instructions SETB and CLR. ex: SETB ACC.3 ; will set bit number 4 (remember bit 0) in the register in 8051 there are many bit-addressable registers such as A (ACC), B, SCON, PCON, TCON, p0,p1,p2,p3 . best wishes, drdigital.


How do you add and subtract 16 bit numbers using 8051 microprocessor?

The 8051 is a microcontroller, not a microprocessor. To add or subtract, use the ADD or SUBB opcodes.


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A byte is 8 bits. We call a 4 bit quantity is nibble. if a byte addressable memory has a 14 bit address how many nibbles of storage are in this memory?

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What is the meaning of bit addressable?

A register is said to be bit addressable if it's individual bits can be set or reset . e.g, let us suppose we have a 8 bit register named D being d7d6d5d4d3d2d1d0 then it is said to be bit addressable if i can set or reset bit dx using some instruction , e.g in 8051 SETB and CLR are used for this purpose , SETB D.1 makes d0 1 , CLR D.4 makesd3 0.