42.8 kHz is hardly a light frequency. In fact, it's hardly much of a radio frequency.
It has a wavelength of over 4.3 miles, and is capable of communicating only very
low rates of information, like the time code to the 'atomic' clock in your house,
four times a day.
For comparison, the longest wavelength of visible light is about 0.000026 inch .
42.8kHz is definitely not a light frequency, as the other answer mentions. However, there is a light frequency that corresponds to that frequency. If you know anything about music, you know a little about octaves: One note and another can be the same note at different pitches. How this happens is a doubling of frequency. If you are looking for a light frequency that corresponds to 42.8kHz, you have to double it, then double that, and keep doubling until you reach a number that falls within 430-770THz. So if you use your calculator to double the number, you will eventually reach the number 735,289,401,075,200Hz or around 735.3THz(to reach this number you would have to double 34 times). This frequency falls within the Violet range of the visible light spectrum(680-790THz) with a wavelength of about 415 nm.
38 kHz
If the first harmonic of 1 kHz is 2 kHz, then the second harmonic is the odd order harmonic of 3 kHz.
40 kHz
The Nyquist frequency for a signal with a maximum bandwidth of 1 KHz is 500 Hz, however that will lead to aliasing unless perfect filters are available. The Nyquist rate for a signal with a maximum bandwidth of 1 KHz is 2 KHz, so the answer to the question is 2 KHz, or 500 microseconds.
No it will not. Think of a radio - you won't receive a station that is broadcasting on 200 khz while tuned to 192 khz.
The minimum sample rate required to record a frequency of 96 kHz is 192 kHz. This is because according to the Nyquist theorem, the minimum sampling rate must be at least twice the highest frequency in order to accurately reconstruct the original signal. So for a frequency of 96 kHz, the minimum required sampling rate is double, which equals 192 kHz.
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
For any wave, frequency x wavelength = speed (of the wave). In this case, convert the kHz to Hz, then divide the speed of light by this frequency. The speed of light should be in meters/second. The answer will be the wavelength in meters.
Assuming that the receiver uses a high-side local oscillator and an IF of 455 KHz, the image frequency is 910 KHz above. When tuned to 1600 KHz, the image frequency would be 2,510 KHz.
If 10 V input causes a frequency shift of 4 kHZ then 2,5v causes a freuency shift of 1 kHz. The input signal frequency of 1 kHz is irelevant.
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
Trovan 128 Khz and ISO 134 Khz
The period of a wave is the inverse of its frequency, so for a wave with a frequency of 0.50 kHz, the period is 1 / 0.50 kHz = 2 milliseconds.
The maxium frequency swing in FM is ± 75 kHz so 75 kHz x 60% = ± 45 kHz
30 Hz is equal to 0.03 kHz. This conversion is done by dividing the frequency in Hertz by 1000.
The standard US AM band is 520 kHz-1,610 kHz. The mean would be at 1,065 kHz.
kHz (kilohertz) is a unit of frequency, not a unit of speed.