Everything Depends on the voltage supply ...... Current flow (Amp) = Watt / Voltage the Current flow will be 1 amp if voltage is 1 V the Current flow will be 0.5 amp if voltage is 2 V the Current flow will be 0.25 amp if voltage is 4 V and so on.......
Watt
The current is the same going into a bulb as it is coming out.
A 100 watt 220 volt light bulb (or anything consuming 100 watts on 220 volts) draws 100/220, or .45 Amps. It will also have about 220²/100, or 484 ohms resistance. A 60 watt 220 volt light bulb (or anything consuming 60 watts on 220 volts) draws 60/220, or .27 Amps. It will also have about 220²/60, or 807 ohms resistance.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
current consumtion of a bulb
A 60 watt bulb at 12 volts will pull 5 amps of current.
No, they do not draw the same current. The current drawn by an electrical device is determined by the power (Watts) and voltage (Volts) using the formula: Current (amps) = Power (Watts) / Voltage (Volts). So, the 12 volt 50 watt bulb will draw higher current compared to the 230 volt 50 watt bulb.
The current is 0.83 amps on 120 v or 0.42 amps on 240 v.
No, a higher wattage INCANDESCENT light bulb uses more current than a lower wattage INCANDESCENT light bulb. Some CF and LED bulbs are rated by the amount of light that an incandescent bulb would produce, but they are also rated by the wattage that they use.
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
As long as the lamp holder will take the larger wattage lamp and the current of the circuit is sized to take the larger current then yes, the lamps should be interchangeable.
Considering an incandescent bulb and using P=VxI P= Power Watts V= Volts I= Current (amperes) I=P/V I=75Watts/120Volts = 0.625 Amperes (A or Amps) Therefore the current through a 75watt bulb that is connected to a 120volt circuit is 0.625 amps.
You can get a 65-watt alternator to generate the current, or alternatively it can be bought from the electricity supply company in many locations.
voltage, current and power factor
To answer this question a voltage must be given.
The property that allowed Edison's first light bulb to light up was the flow of electric current through a conductive filament, typically made of tungsten or carbon. This flow of current passed through the filament, heating it up to a high enough temperature to emit light.