The current flowing through a bulb is equal to the (voltage across the bulb) divided by the
(bulb resistance), and can be expressed in Amperes.
The rate at which the bulb dissipates energy is equal to (voltage across the bulb)
times (current through the bulb), and can be expressed in watts.
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Everything Depends on the voltage supply ...... Current flow (Amp) = Watt / Voltage the Current flow will be 1 amp if voltage is 1 V the Current flow will be 0.5 amp if voltage is 2 V the Current flow will be 0.25 amp if voltage is 4 V and so on.......
The current is the same going into a bulb as it is coming out.
Watt
A 100 watt 220 volt light bulb (or anything consuming 100 watts on 220 volts) draws 100/220, or .45 Amps. It will also have about 220²/100, or 484 ohms resistance. A 60 watt 220 volt light bulb (or anything consuming 60 watts on 220 volts) draws 60/220, or .27 Amps. It will also have about 220²/60, or 807 ohms resistance.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.