Adding more loads in a parallel circuit increases the current because of Kirchoff's voltage and current laws, and because of Ohm's law...
1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.
2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.
3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.
V=IRyou are adding in parallel, so V is non-zero, because R is positive, I must have the same sign as V. Therefore your current will increase.
by adding resistance in parallel more current is bound to flow
Adding more lamps in parallel (across) a line will cause total current to climb. It will keep climbing (increasing) until a load protection device (circuit breaker or fuse) breaks the circuit or until something fails because of excessive current.
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
Adding more branches to a parallel circuit decreases the overall resistance of the circuit. This leads to an increase in the total current flowing through the circuit as each branch provides an additional pathway for the current to flow. This results in a decrease in the total resistance and an increase in the overall current of the circuit.
V=IRyou are adding in parallel, so V is non-zero, because R is positive, I must have the same sign as V. Therefore your current will increase.
When more bulbs are added to a parallel circuit, the total current in the circuit increases because each bulb provides an additional path for current to flow. This is because in a parallel circuit, the current is divided amongst the branches, so adding more branches (bulbs) will increase the total current.
In a parallel circuit, the total amperage increases as the number of bulbs increases because the current has multiple paths to flow through. Each bulb offers a separate path that allows more current to flow. In a parallel circuit, adding more bulbs decreases the total resistance, allowing more current to pass through.
Current can be increased by adding a larger load to the circuit.
by adding resistance in parallel more current is bound to flow
The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total. By removing a resistor the total current will lower. If you short out the parallel circuit as suggested it will take out the fuse that should be protecting the circuit.AnswerShorting-out a resistor in a parallel circuit, will act to short out the entire circuit, therefore, significantly increasing, not lowering, the current! And, as the previous answer indicates, this short-circuit current will operate any protective devices, such as a fuse.In a parallel circuit current does not lower but it will be increase if shorting-out one resistor in the two resistor parallel circuit, the circuit will become very low resistive and the larger current will flow through the short path.
Adding a load in parallel to a parallel circuit would decrease the total resistance of the circuit, causing an increase in total current. This would result in each load receiving more current, potentially affecting the individual voltage drops across each load.
The supply voltage in a parallel circuit remains the same regardless of the number of additional resistors connected. The voltage across each resistor in a parallel circuit is the same as the supply voltage. Adding more resistors in parallel will increase the total current drawn from the supply.
Adding more lamps in parallel (across) a line will cause total current to climb. It will keep climbing (increasing) until a load protection device (circuit breaker or fuse) breaks the circuit or until something fails because of excessive current.
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
When more light bulbs are added to a parallel circuit, the total resistance decreases because each additional bulb provides an additional pathway for current to flow. This results in an increase in the overall current flowing through the circuit, as well as an increase in the total power consumed by the circuit.