0
The program goes as follows:
#include
#include
void main()
{
int i, j=1;
printf("Enter the value of the integer whose factorial has to be calculated");
scanf("%d",i);
while(j
i = i*(i-1);
i--;
printf("The factorial of the integer is:%d",i);
getch();
}
OTHER METHOD.............
#include
#include
void main()
{
int n,f;
f=1;
printf("Enter the number:\n");
scanf("%d",&n);
while(n>0)
{
printf("%d",n);
f=f*n;
n--;
}
printf("The factorial of the integer is:%d",f);
getch();
}
another method
A very easy method,,,,,,
these is the work of 2nd year high school programming........... CVHS..
#include
int main()
{
char m;
int ans, i, n;
i=0;
m='y';
while((m=='y')(m=='Y'))
{
cout<<"Input a number ";
cin>>n;
if(n==0)
{
ans=1;
cout<<"The factorial of a number is "< } else { ans=1; for(i=1;i<=n;i++) { ans=ans*i; } cout<<"The factorial of a number is "< } cout<<"\n Do you want to continue? (Y/N) "; cin>>m; } return 0; } see,, its very easy!!!! my new mathod #include #include main() { int i,j,div,mod; clrscr(); printf("enter any number = "); scanf("%d",&i); for(j=1;j<=i;j++) { mod=i%j; if(mod==0) { printf("%d*",j); div=i/j; i=div; j=1; } } if(j==i) { printf("%d",i); } getch(); }
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Jordan
Professor// Note: You may need a larger data type, factorials become very big very quickly and may cause an overflow
long factorial(int x)
{
if(x == 1)
return 1;
return((long) factorial(x-1) * x);
}
There are several methods, some recursive, and iterative. Most suffer from lack of precision, because factorials get large fast. Here is a routine that compares various methods, including a method of arbitrary length decimals using linked lists. Note that, in order to compute vary large factorials, you will need to tell your linker/binder to increase the run-time stack size, because the linked list is created on the stack, and not in the heap.
// Factorial.cpp : Defines the entry point for the console application.
//
#include <stdlib.h>
#include <stdio.h>
/* Microsoft 32-bit iterative */
unsigned long NFactLongIterative (unsigned long N) {
unsigned long result = N;
if (N < 2) return 1;
if (N 2) {
decimal_initialize (d, 2);
return;
}
while (N > 2) {
decimal_multiply (d, N);
N--;
}
return;
}
/* Example main line */
/* Generates all variations to show differences in results */
int main (int argc, char *argv[]) {
int N;
decimal Decimal = {2, NULL};
if (argc < 2) {
printf ("Enter N (or use command line) : ");
scanf_s ("%d", &N);
} else {
N = atoi (argv[1]);
}
printf ("Long: %u! = %u\n", N, NFactLongIterative (N));
printf ("LongLong: %u! = %I64u\n", N, NFactLongLongIterative (N));
printf ("Recursive: %u! = %I64u\n", N, NFactLongLongRecursive (N));
printf ("Double: %u! = %.0f\n", N, NFactDouble (N));
/* note: arbitrary is exact - if the others don't match, arithmetic overflow occurred */
printf ("Arbitrary: %u! = ", N);
decimal_NFactIterative (&Decimal, N);
decimal_print_digits (&Decimal, true);
return 0;
}
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Write a recursive procedure to compute the factorial of a number?
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
Programming to calculate a factorial number?
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
Write the program that display the factorial of a number?
/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }
How you can find a factorial of a number without using multiple operator?
If you really wanted to do this, you could simulate multiplication with repeated addition.
Program to find factorial of a number using inheritance?
/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }
Write a recursive procedure to compute the factorial of a number?
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
Programming to calculate a factorial number?
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
Program for finding the factorial of the two given number using constructor?
kjhk
By using call by reference find the factorial of a number?
chutia mc,bc bhosdika
How can you get the number 25 by using only number 4?
(4 times 4 factorial + 4) divided by 4 4 factorial + the square root of 4 minus (4 divided by 4)
What is a Flow chart for finding factorial of a given number using recursion function?
no answer....pls post
Program to find n th fabonacci number?
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(const int& N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
How do you make the number 11 using only 4' s?
(4!+4!-4)/4 ! means factorial, A factorial is every number below it multiplied Ex. 4!=4x3x2x1 which = 24(24+24-4)/4
Write the program that display the factorial of a number?
/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }
7 Write a C program to compute the factorial of a number using for loop?
int factorial(int n) { int i; int f=1; for(i=2;i<=n;++i) f*=i; return f; }
Program in c to generate table of factorials?
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(int N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
How you can find a factorial of a number without using multiple operator?
If you really wanted to do this, you could simulate multiplication with repeated addition.
