by connecting a multimeter u can measure
Measure the voltage appearing across each resistor. If they are identical, and equal to the supply voltage, then the resistors are in parallel.
Because the two voltages are out of phase, that means that individually they peak at different times in the AC cycle, so in general if they are measured separately their sum will exceed the supply voltage, possibly by up to 41%.
To find the voltage drop across a relay, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). In this case, the current is 0.0015 amps and the resistance is 12,000 ohms. Therefore, the voltage drop can be calculated as V = I × R = 0.0015 A × 12,000 Ω = 18 volts. Thus, the voltage drop across the relay is 18 volts.
I don't think you can do that, with the information provided.
In a series circuit, the potential difference (voltage) across the entire circuit is equal to the sum of the potential differences across each individual component. To find the potential difference across a specific component, you can use Ohm's Law (V = I × R), where V is the voltage, I is the current through the circuit, and R is the resistance of that component. The total voltage supplied by the source is equal to the sum of the voltages across all components, so V_total = V1 + V2 + V3 + ... + Vn.
To find the power output of a light bulb, you can use the formula ( P = V \times I ), where ( P ) is the power in watts, ( V ) is the voltage across the bulb in volts, and ( I ) is the current flowing through it in amperes. You can measure the voltage using a voltmeter and the current with an ammeter. Alternatively, if the bulb has a specified wattage rating (e.g., 60W), that value represents its power output directly.
string efficiency= voltage across the string ---------------------------------------- (N*voltage across the most stressed unit) N is the number of units in the string
string efficiency= voltage across the string ---------------------------------------- (N*voltage across the most stressed unit) N is the number of units in the string
db gain is defined as power gain, not voltage gain. Please restate you question in terms of power, or provide details of input and output impedance.
Tell me what car the fuel tank is located in and I will tell you the fuel capacity.
Measure the voltage appearing across each resistor. If they are identical, and equal to the supply voltage, then the resistors are in parallel.
Batteries are a voltage storage device that hold a voltage potential until used. By using a volt meter you can find the stored voltage by placing the leads of the meter across the battery's positive and negative terminals.
Solar cells produce electricity rather than store voltage. The voltage produced by a solar cell depends on factors like sunlight intensity and cell characteristics. You can measure the voltage generated by a solar cell using a multimeter or similar device.
A: Simply by adding a series resistor from the battery charger. WHAT VALUE? find the current required and use it to IR drop the voltage
P(watts) = I (current) times E (voltage) hence it is known as the pie formula P=IE
Because the two voltages are out of phase, that means that individually they peak at different times in the AC cycle, so in general if they are measured separately their sum will exceed the supply voltage, possibly by up to 41%.
To find the voltage drop across a relay, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). In this case, the current is 0.0015 amps and the resistance is 12,000 ohms. Therefore, the voltage drop can be calculated as V = I × R = 0.0015 A × 12,000 Ω = 18 volts. Thus, the voltage drop across the relay is 18 volts.