Facts missing. Need two of three values. The resistors value. The voltage across it. The current flowing through it. P=I^2*R. P=E^2/R
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if R4 is the only resistor (the load), then the drop would be the same as the energy source
Three lead RTD is an industrial standard when a bridge arrangement is used. The advantage of this design is it distributes resistance due to the connecting leads equally to the adjacent arms of the bridge making lead resistance insignificant and avoids any error due the same. When it comes matter of using xtr we need to add lead resistance with the R4 as given in the datasheet of texas. This can be done by using a variable resistance for R4 and do change the R4 such that the output current becomes 4mA for lower bound of range.. (ie) (their is no need to use the 3 lead RTD for accuracy same accuracy can acheived here with 2 lead RTD. just by having a variable resistor R4)
Answer: The equivalent resistance of a series of resistors is as follows:Suppose you have three 120 Ohm resistors:A---/\/R1\/\------/\/R2\/\------/\/R3\/\---BThe equivalent resistance of point A to point B is the resistance of R1, R2 and R3 in series.Suppose we would want to replace R1, R2 and R3 with a single resistor, R4:A---/\/R4\/\---BThe resistance of R4 would be 360 Ohms, since equivalent resistance of a series combination is:Req = R1 + R2 + R3Answer: What is meant by equivalent resistance is that if you replace (for example) two or three circuits with whatever you calculate (see the other reply, above) as the "equivalent resistance", the effect on the circuit in general will be the same. For example, the same amount of current will flow.
It contains an address, which will be used in calculting the actual address of an operand. Example (Sytem/360): L R2,12(R3,R4) meaning: tempadd := 12 + R3 + R4 R2 := content of memory at tempadd here R3 is called base registed, R4 is called index register. Or vice versa.
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms