1 horsepower is equal to 0.7456 kWatts, therefore 1.1184 kWatts will be the power consumption of that motor.
The current draw depends on the voltage, simply use the P=UxI or I=P/U formulas to figure out the current draw (P=1118.4 Watts).
some voltages:
12Vdc draw 93.2Amps
24Vdc draws 46.6Amps
110Vdc draws 10.17Amps
230Vdc draws 4.86Amps
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A 1 hp motor draws around 750 watts just divide it by 12 volts = Amps.... so its 62.5 amps
Motors do not put out amperage. A motor draws amperage as a load on an electrical system. A generator is used to produce voltage and amperage governed by the load connected to the generator.
To answer this question the voltage of the motor must be stated.
The wiring should allow for 115 amps.
A 15 amp circuit breaker should trip at 15 amps regardless of the load voltages or impedances. If you have 277 volts and 7 ohms, the current would be 39.5 amps and a 15 amp circuit breaker should trip.
The formula you are looking for is I = kW x 1000/1.73 x E x pf. I = 1.5 x 1000 = 1500. 1500/1.73 x 400 x .86 = 1500/595 = 2.5 amps. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. A feeder for a motor has to be rated at 125% of the motors full load amps 2.5 x 125% = 3.1 amps A #14 copper conductor with an insulation rating of 90 degrees C is rated at 15 amps.
At 600 volts the rule of thumb is one amp per horsepower. So a 20 HP motor would need 20 amp wire. The code book states that a 20 HP motor at 575 volts draws 22 amps. The conductor for a motor has to be 125% rating of the motors FLA (full load amps). 22 x 125% = 27.5 amps. A #10 copper conductor with a insulation factor of 60,75 or 90 degrees C is rated at 30 amps.