Current in 200kw at 480 volts = 200,000/480 = 416.667 amps
90 kW on 480 volts single phase would be 187.5 amps. On 480 v 3-phase it would be 108 amps.
This 480-v three-phase transformer probably has a 208-v three-phase secondary which has 120 v from each line to neutral. In that case the primary current is 0.433 times as much as the secondary current, so 100 amps in the secondary means 43.3 amps in the primary.
96 kW means 32 kW from each phase. If the load is star connected each resistor has 277 volts across it and carries 32,000/277 amps, 115.5 amps. The load resistors are 277/115.5 ohms or 2.40 ohms If the load is delta connected each resistor has 480 volts across it and carries 66.7 amps. The load resistors are 480/66.7 ohms or 7.20 ohms. In both cases the line current is 115.5 amps.
The figure 1.73 is the results of the square root of 3. 1.73 is used in three phase calculations. The number is also used on three phase four wire systems. To find the coil voltages of a wye system 1.73 is divided by the phase voltage. An example, three phase 480 wye system. 480/1.73 = 277 volts
Current in 200kw at 480 volts = 200,000/480 = 416.667 amps
88 amps
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
90 kW on 480 volts single phase would be 187.5 amps. On 480 v 3-phase it would be 108 amps.
50 kVA is 16.667 kVA per phase and you divide that by the phase voltage. Current = 16667 / 277 = 60 Amps
480 volts is probably 3-phase (Line to line) voltage, so: 1500K / (480 x 1.732) = I = 1804Amps
1.73*480*22
if it's single-phase, 25,000 divided by 480.
This 480-v three-phase transformer probably has a 208-v three-phase secondary which has 120 v from each line to neutral. In that case the primary current is 0.433 times as much as the secondary current, so 100 amps in the secondary means 43.3 amps in the primary.
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
24 amps. This could be three 11.54 resistors connected in star, or three 34.6 ohm resistors connected in delta.
The heater should have a wattage rating (very few list amps). Calculate the amps using the wattage and voltage. Amps = Watts/Volts(480).