How do you write 55555 4444 333 22 1 in java?

Answer 1

You can do this with a nested loop:

public static void main(String[] args){

for(int i=5, i>0, i--){

for(int j=i, j>0; j--)

System.out.print(i);

System.out.print(' ');

}

}

The outer loop decrements the integer that you are printing and the inner loop will print the integer the number of times equal to its value.

Answer 2

To print the given sequence in Java, you can use a loop to iterate through each number and print it the corresponding number of times. Here's an example code snippet to achieve this:

public class NumberSequence {
    public static void main(String[] args) {
        int[] numbers = {5, 4, 3, 2, 1};
        
        for (int num : numbers) {
            for (int i = num; i >= 1; i--) {
                System.out.print(num);
            }
            System.out.print(" ");
        }
    }
}

This code will output: 55555 4444 333 22 1

Answer 3

for (int x=5; 0<x; --x){

for (int y=0; y<x; ++y){

System.out.print (x);

}

System.out.print (' ');

}