You have to know 2 things in order to perform the calculation. You will need to know the power (KW) and either the amps or the voltage. If you know voltage you can determine amps and if you know amps you can determine voltage. However with solely the KW you do not have enough information to calculate either. Here is the formula:
1 Phase: KW = (E x I x pf)/ 1000
3 Phase: KW = (1.732 x E x I x pf)/1000
Where E is voltage, I is current, and pf is Power Factor
You first have to find out what the load amperage is going to be and second, what is the working voltage.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
Since the breaker that is installed on the generator set will be sized to the output of the 30 kW generator, the load will stay connected until the thermal trip of the breaker trips the load off line. This will be in the matter of seconds before it happens. To handle a 75 kW load and depending if it is an inductive or a resistive load you will need at least a 80 to 100 kW generator.
A 7.5 kW three phase load will be balanced by the manufacturer. When connected to a three phase source the line current on each phase will be equal.
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
Yes I could. How?
You first have to find out what the load amperage is going to be and second, what is the working voltage.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
0.0075 kw
It does not matter, when testing a generator with a resistive load bank, if you load it to kVA or KW. For a resitive load, i.e. non-reactive load, the power factor is one, so kVA and kW are the same.
To find the minimum kW service demand load for twenty 6.5 kW ranges in a multifamily dwelling, you would simply multiply the number of ranges by the kW rating of each range. In this case, 20 ranges x 6.5 kW = 130 kW minimum service demand load.
Since the breaker that is installed on the generator set will be sized to the output of the 30 kW generator, the load will stay connected until the thermal trip of the breaker trips the load off line. This will be in the matter of seconds before it happens. To handle a 75 kW load and depending if it is an inductive or a resistive load you will need at least a 80 to 100 kW generator.
A 7.5 kW three phase load will be balanced by the manufacturer. When connected to a three phase source the line current on each phase will be equal.
To calculate kilovolt-amps (kVA) when kilowatts (kW) is known, you can use the formula: kVA = kW / power factor. The power factor is the ratio of real power (kW) to apparent power (kVA) in an electrical circuit.
It depends on the total connected load (KW) of the house. If the total connected load is about 20 KW the alternator generator should be designed to meet peak 20 kw load
3phese 460 volt 75 kw a/c drivi full load current
Rating for DG set and any of electrical machines is calculated in KVA. KVA is calculated as KW/pf. One can calculate the required KVA for DG set with this formulation: (KW/pf)/load rate. For example KW=110, pf=0.8 and one loads the DG at 75%, so KVA= (110/0.8)/0.75=185 KVA.