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The value of each main scale divisions is half a degree(30') .
The number of vernier scale divisions is 30.
29 main scale divisions are divided into 30 vernier scale divisions (30 VSD = 29 MSD )
Therefore value of 1 VSD = 29/30 MSD.
Least Count (L.C.) = 1MSD - 1VSD
= 1MSD - 29/30 MSD
= 1/30 MSD
= 1/30 x 30'
(L.C.) = 1' (1 minute)
Wiki User
∙ 11y ago
Wiki User
∙ 12y agoFinding least count of spectrometer
1. Count the total number of division on the vernier scale, say, n. Note the smallest
division on the circular scale in minutes, say, m minutes.
2. The least count is the smallest division divided by the number of divisions on the
vernier, i.e., it is m
n minutes.
Wiki User
∙ 11y agosmallest no of division on main scale/ total no of vernier scale
Wiki User
∙ 11y agoLeast Count = value of 1 main scale reading/total no.of vernier divisions.
Lc=30'/30=1'.
krishna sharma
Wiki User
∙ 12y agovalue of 1 MSD/ no.of VSD for a vernier.
Anonymous
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Hi, heres how you calculate least count of a micrometer. Use the given formula: Least Count (L. C) = Pitch/no. of divisions on micrometer barrel(thimble) where, Pitch = distance travelled by thimble on linear scale in one rotation. Hi, heres how you calculate least count of a micrometer. Use the given formula: Least Count (L. C) = Pitch/no. of divisions on micrometer barrel(thimble) where, Pitch = distance travelled by thimble on linear sacle in one rotation.
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