How can you write an algorithm to read two numbers then display the smallest?

Answer 1

/* program to calculate sum of two no.s in c*/

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,sum; clrscr();

cout("enter 2 nos");

cin("%d %d ",&a,&b);

sum=a+b;

cout("sum is %d",sum);

getch();

}

Answer 2

Its easy

#include<stdio.h>

main()

{

int i,j;

printf("\n Enter any number : ");

scanf("%d", &i);

printf("\n Enter any number which is not equal to earlier : ");

scanf("%d", &j);

if (i<j)

printf("\n The smaller one is %d", i);

else

printf("\n The smaller one is %d", j);

}

Also int can be replaced with float and all the %d with %f to handle the float user input

also elseif can be added for output of equal numbers entered by user as below

#include<stdio.h>

main()

{

int i,j;

printf("\n Enter first number : ");

scanf("%d", &i);

printf("\n Enter second number : ");

scanf("%d", &j);

if (i<j)

printf("\n The smaller one is %d", i);

elseif (i==j)

printf("\n Both the numbers equal!");

else

printf("\n The smaller one is %d", j);

}

Answer 3

The details vary from one programming language to another. In general, you can write instructions to ask the user for input. You can also write a function that doesn't ask for input, but rather accepts two parameters (in which case, ANOTHER part of the program will pressumably ask for input, then pass the information on to the function).

Answer 4

Algorithm smallest Is:-

Input: two values, a and b

Output: smallest value of a and b

if a<b then return a else return b

In C Programming:

long double smallest (long double a, long double b) { return a<b?a:b; }

Answer 5

Just use a series of ifs to check whether a < b, a > b or a == b.