What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
The resistance will be: 1/(1/100+1/80)+100=144.4444444444
Four 100 ohm resistors in parallel have an effective resistance of 25 ohms.
Short circuit
Req=0
A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.
What do you mean? In a parallel circuit, the combined (or effective) resistance is less than any individual resistance.
To find equivalent resistance when you have both parallel and series resistors, start simple and expand... Find the smallest part of the circuit, such as a pair of resistors in series or a pair of resistors in parallel, and compute the equivalent single resistor value. Repeat that process, effectively covering more and more of the circuit, until you arrive at a single resistance that is equivalent to the circuit. For resistors in series: RTOTAL = R1 + R2 For resistors in parallel: RTOTAL = R1R2/(R1+R2)
when we want maximum resistance they are connected in series. when resistors are connected in series total resistance is maximum when resistors are connected in parallel total resistance is minimum for series total R=R1+R2+R3......... for parallel R1 in parallel to R2 total 1/R=(1/R1)+(1/R2) ie R=(R1*R2)/(R1+R2)
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.
A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.
resistance inparallel decrease in value proportionally two resistance can be calculated as R1XR2/SUM OF R1+R2. many values can be calculated as a fraction 1/r+1/r2+1/3 ....and take the total sum reciprocal
What do you mean by a 'parallel delta' circuit -is there such a connection.
In principle, it is infinite. I have not connected a parallel circuit in ages.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
If additional resistance is connected in parallel with a circuit the supply voltage will decrease?
No change in supply voltage as additional resistance is connected in parallel circuit.
What do you mean? In a parallel circuit, the combined (or effective) resistance is less than any individual resistance.
To find equivalent resistance when you have both parallel and series resistors, start simple and expand... Find the smallest part of the circuit, such as a pair of resistors in series or a pair of resistors in parallel, and compute the equivalent single resistor value. Repeat that process, effectively covering more and more of the circuit, until you arrive at a single resistance that is equivalent to the circuit. For resistors in series: RTOTAL = R1 + R2 For resistors in parallel: RTOTAL = R1R2/(R1+R2)
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
when we want maximum resistance they are connected in series. when resistors are connected in series total resistance is maximum when resistors are connected in parallel total resistance is minimum for series total R=R1+R2+R3......... for parallel R1 in parallel to R2 total 1/R=(1/R1)+(1/R2) ie R=(R1*R2)/(R1+R2)