Assembly language code for the Conversion of ascii to binary using 8085 microprocessor?

Answer 1

Org 1000

mov si,1100

mov di,1400

cld

mov bl,20h

next: lodsb

cmp al, bl

je exit

sub al,30h

cmp al,0ah

jc store

sub al,07h

store: stosb

jmp next

exit: hlt

Answer 2

As you did not specify, I will assume you are talking about three-bit binary-reflected gray code. The procedure for other possible codes and lengths would be similar.

The code table of three-bit gray code
D bin gray D'
0 000 000 0
1 001 001 1
2 010 011 3
3 011 010 2
4 100 110 6
5 101 111 7
6 110 101 5
7 111 100 4

The format of this table is:
Decimal number; bits B2,B1,B0 of natural binary number; bits G2,G1,G0 of binary number in gray code; decimal representation of the gray code number

To get natural binary numbers from the gray numbers, we need to follow the algorithm defined by the table:
( Dec' -> Dec )
zero stays zero
one stays one
three becomes two
two becomes three
six becomes four
seven becomes five
five becomes six
four becomes seven

Let us search for rules in the transformation, so our program can detect which number it is working with and how to change it to natural binary.
Both 0 and 1 don't change. Their shared property is 00 in the higher two bits.
3 and 2 change places. They both have 01 in higher two bits, and the program should toggle the lowest bit.
Next we have the circular changes 7 -> 5 -> 6 -> 4 -> 7. This is a bit trickier, but if we analyse their binary forms, we can see that any number that has 10 in its top two bits needs to have its low two bits toggled (ie. 100 becomes 111, and 101 becomes 110). Similarly, those numbers with 11 in top two bits need to have their middle bit set to 0 (ie. 110 becomes 100 and 111 becomes 101).

In essence, the program should check for the two higher bits, and depending on the values there, perform one of these four operations. That check can be done in several ways, depending on what you can do with your microcontroller. Perhaps the easiest would be using a mask to set all other bits to zero and analysing what's left.

Answer 3

// INCLUDE HEADER FILES NEEDED BY YOUR PROGRAM

// SOME LIBRARY FUNCTIONALITY MAY BE RESTRICTED

// DEFINE ANY FUNCTION NEEDED

// FUNCTION SIGNATURE BEGINS, THIS FUNCTION IS REQUIRED

int grayCheck(char term1, char term2)

{

// WRITE YOUR CODE HERE

}

// FUNCTION SIGNATURE ENDS

// DO NOT IMPLEMENT THE main( ) METHOD

int main()

{

//DO NOT CHANGE ANY CODE IN THIS FUNCTION

int a;

char c1,c2;

//ASSUME INPUT HAVE ALREADY BEEN TAKEN

a=grayCheck(c1, c2);

return 0;

}

Answer 4

Lda 8050h

cpi oah

jnc l1

adi 07h

adi 30h

sta 9000

hlt

Answer 5

just add 3 to the number which you want ti convert into gray code

Answer 6

45