Wiki User
∙ 13y agoIf you have access to a calculator: Click cos-1 then .86 to get an answer of 30.6834
Wiki User
∙ 13y agoIn a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
90 degrees
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
In this case current flows from a high voltage to a lower voltage in a circuit.
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
90 degrees
In a very simple way. As long as nothing changes in the circuit, the current that flows from the power supply or battery into the circuit is directly proportional to the voltage of the supply. -- If you double the voltage across the ends of the circuit, the current will double. -- If you turn the voltage up to 3.4027 times its original value, the current will increase to 3.4027 times its original value. -- If you decrease the voltage by 81.7 percent, the current will decrease by 81.7 percent.
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
90 degrees. In an AC circuit with a pure capacitance, the current leads the voltage by 90 degrees. This is because the current in a capacitor is proportional to the rate of change of voltage across it, leading to this phase relationship.
The phase angle between voltage and current in a purely inductive circuit, under ideal circumstances where there is no resistance at all, is 90 degrees.
ICE current leads the voltage by 90 degrees.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
In an inductive circuit, the current lags behind the voltage due to the energy stored in the inductor's magnetic field. The voltage leads the current by 90 degrees in an ideal inductive circuit. The relationship between voltage and current is described by the equation V = L di/dt, where V is voltage, L is inductance, di is change in current, and dt is change in time.
In a pure resistive circuit the voltage and current are in phase. In an inductive circuit they are fro zero to 180 degrees out of phase. If they are in phase the Power Factor is 1 and 180 degrees the PF is zero. The exact amount of the phase difference depends on the specific circuit.
Changing the voltage in a circuit will alter the current flowing through it. According to Ohm's Law, the current is directly proportional to the voltage in the circuit. Increasing the voltage will lead to an increase in current, and vice versa.
In a capacitor, the current LEADS the voltage by 90 degrees, or to put it the other way, the voltage LAGS the current by 90 degrees. This is because the current in a capacitor depends on the RATE OF CHANGE in voltage across it, and the greatest rate of change is when the voltage is passing through zero (the sine-wave is at its steepest). So current will peak when the voltage is zero, and will be zero when the rate of change of voltage is zero - at the peak of the voltage waveform, when the waveform has stopped rising, and is about to start falling towards zero.