report zbharath.
data:num type i value 5,
fac type i value 0.
perform fact using num changing fac.
write:/ 'factorial of',num,'is',fac.
form fact.
using value(f-num) type i.
changing f-fact type i.
f-fact=1.
while f-num ge 1.
f-fact=f-fact*f-num.
f-num=f-num-1.
endwhile.
endform.
Pseudo code+factorial
/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
since factorial is for example , the factorial of 5 = 5 (5-1)(5-2)(5-3)(5-4) that means the last number to subtract from 5 is 4 , which is (n-1) ie the factorial of any number is (n-0)(.............)(n-(n-1)) to write this , 5 REM to calculate the factorial of any number 6 DIM fac AS INTEGER LET fac = 1 10 INPUT "enter the number to find its factorial "; a ' variable a 15 FOR b = 0 TO (a-1) 'numbers that will be subtracted from the " a" 20 c= a -b 'each number in the factorial calculation 25 fac = fac * c 'to compute each multiplication in the factorial 30 NEXT b 35 PRINT 'to leave a line 40 PRINT fac 45 END note this due to some unattained raesons works for numbers 0 to 7
/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }
Here's a simple Java program to find the factorial of a given number using a recursive method: import java.util.Scanner; public class Factorial { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int number = scanner.nextInt(); System.out.println("Factorial of " + number + " is " + factorial(number)); } static int factorial(int n) { return (n == 0) ? 1 : n * factorial(n - 1); } } This program prompts the user for a number and calculates its factorial recursively.
In a C program that calculates the factorial of a number using a function, the program typically prompts the user for an integer input. The function then recursively or iteratively computes the factorial by multiplying the number by the factorial of the number minus one until it reaches one. For example, if the user inputs 5, the program outputs 120, as 5! = 5 × 4 × 3 × 2 × 1. The final result is displayed on the screen.
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
Pseudo code+factorial
this is a code for calculating it recursivelly: float Factorial (float n) { if (n<=1) return 1.0; else return n* Factorial(n-1); }
/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }
A flowchart to find the factorial of a given number typically includes the following steps: Start, read the input number, check if the number is less than 0 (return an error for negative numbers), initialize a result variable to 1, and then use a loop to multiply the result by each integer from 1 to the input number. The algorithm can be summarized as follows: if ( n ) is the input number, initialize ( \text{factorial} = 1 ); for ( i ) from 1 to ( n ), update ( \text{factorial} = \text{factorial} \times i ); finally, output the factorial.
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
i need a pic of cuson
#file.sh#run as sh file.shecho "Enter the no."read ni=nr=1while [ $i -ge 1 ]dor=`expr $r \* $i`i=`expr $i-1`doneecho Factorial is $rIf the ans helps you,plz increase the trust point.
I suggest to use a for loop, more or less like this (assuming the parameter is "n"): product = 1; for (int i = 1; i <= n; i++) { product *= i; }