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report zbharath.

data:num type i value 5,

fac type i value 0.

perform fact using num changing fac.

write:/ 'factorial of',num,'is',fac.

form fact.

using value(f-num) type i.

changing f-fact type i.

f-fact=1.

while f-num ge 1.

f-fact=f-fact*f-num.

f-num=f-num-1.

endwhile.

endform.

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Write the Pseudocode to find the factorial of a number?

Pseudo code+factorial


Program to find factorial of a number using inheritance?

/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }


Using while loop Write a program find the factors of a number?

by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }


How do you create factorial program in qbasic?

since factorial is for example , the factorial of 5 = 5 (5-1)(5-2)(5-3)(5-4) that means the last number to subtract from 5 is 4 , which is (n-1) ie the factorial of any number is (n-0)(.............)(n-(n-1)) to write this , 5 REM to calculate the factorial of any number 6 DIM fac AS INTEGER LET fac = 1 10 INPUT "enter the number to find its factorial "; a ' variable a 15 FOR b = 0 TO (a-1) 'numbers that will be subtracted from the " a" 20 c= a -b 'each number in the factorial calculation 25 fac = fac * c 'to compute each multiplication in the factorial 30 NEXT b 35 PRINT 'to leave a line 40 PRINT fac 45 END note this due to some unattained raesons works for numbers 0 to 7


Write the program that display the factorial of a number?

/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }

Related Questions

Write a java program to find the factorial of a given number?

Here's a simple Java program to find the factorial of a given number using a recursive method: import java.util.Scanner; public class Factorial { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int number = scanner.nextInt(); System.out.println("Factorial of " + number + " is " + factorial(number)); } static int factorial(int n) { return (n == 0) ? 1 : n * factorial(n - 1); } } This program prompts the user for a number and calculates its factorial recursively.


output of a c program using function to find factorial of a number?

In a C program that calculates the factorial of a number using a function, the program typically prompts the user for an integer input. The function then recursively or iteratively computes the factorial by multiplying the number by the factorial of the number minus one until it reaches one. For example, if the user inputs 5, the program outputs 120, as 5! = 5 × 4 × 3 × 2 × 1. The final result is displayed on the screen.


Program to find the factorial of a number using recursion?

/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }


Write the Pseudocode to find the factorial of a number?

Pseudo code+factorial


C program to find factorial of a no?

this is a code for calculating it recursivelly: float Factorial (float n) { if (n<=1) return 1.0; else return n* Factorial(n-1); }


Program to find factorial of a number using inheritance?

/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }


what is the flow chart and algorithm to find the factorial of a given number?

A flowchart to find the factorial of a given number typically includes the following steps: Start, read the input number, check if the number is less than 0 (return an error for negative numbers), initialize a result variable to 1, and then use a loop to multiply the result by each integer from 1 to the input number. The algorithm can be summarized as follows: if ( n ) is the input number, initialize ( \text{factorial} = 1 ); for ( i ) from 1 to ( n ), update ( \text{factorial} = \text{factorial} \times i ); finally, output the factorial.


Using while loop Write a program find the factors of a number?

by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }


How can you figure out combinations in math?

If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]


Find flow chart for factorial of given number?

i need a pic of cuson


Write a sell program to find the factorial of a number?

#file.sh#run as sh file.shecho "Enter the no."read ni=nr=1while [ $i -ge 1 ]dor=`expr $r \* $i`i=`expr $i-1`doneecho Factorial is $rIf the ans helps you,plz increase the trust point.


Write a program in java to find factorial of a number?

I suggest to use a for loop, more or less like this (assuming the parameter is "n"): product = 1; for (int i = 1; i <= n; i++) { product *= i; }