E/R=I. 100/50=2 amps.
Diodes are rated to use a certain amount of current. If you go over that amount, it will eventually destroy the device, how long it takes to destroy the device depends on how much more current you are running through it than it is rated at.
It depends on the resistance of everything connected between the terminals of the power supply. If the resistance is infinite or very high, there is little or no current. As the resistance becomes less, the current becomes greater. In general, the current through a circuit with 90 volts applied to it is [ 90 / R ], where 'R' is the resistance of everything across the 90-volt power supply.
'Non-examples' of a parallel circuit include seriescircuits, series-parallel circuits, and complexcircuits.
The resistor bypass in the ignition circuit is used when starting the engine. It bypasses the resistor to provide full battery voltage to the ignition coil, ensuring a strong spark for a quick and reliable engine start. Once the engine is running, the bypass is no longer needed and the resistor is re-engaged to limit the voltage to the ignition coil for normal operation.
5 ohms...
To calculate the current running through the 60 ohm resistor in a parallel circuit, you first need to find the total resistance of the circuit. For a parallel circuit, the reciprocal of the total resistance (1/RT) is equal to the sum of the reciprocals of the individual resistances (1/R1 + 1/R2 + 1/R3). Once you find the total resistance, you can use Ohm's Law (I = V/R) to calculate the current running through the 60 ohm resistor.
What is the current running through resistor four?1 amps..!What is the current running through resistor one? 3 amps...!What is the current running through resistor three? 2amps..!What is the current running through resistor five? 3 amps..!What is the voltage drop running through resistor five? 45 volts...!What is the equivalent resistance through the parallel portion of the circuit? 6 ohmsAnswerA resistor is a conductor, albeit one with a higher resistance than a length of wire, so current passes through it without any problem. The magnitude of the current will, of course, be somewhat lower because of the additional resistance.
To calculate the total current in the circuit, you first need to find the total resistance by using the formula for resistors in parallel: 1/Total Resistance = 1/120 + 1/60 + 1/40. Once you have the total resistance, you can use Ohm's Law: Current = Voltage / Total Resistance. Finally, to find the current running through the 40 ohm resistor, you divide the total current by the resistance of the 40 ohm resistor.
1amp
To find the current through the 40 ohm resistor, first calculate the total resistance of the parallel circuit: 1/Rt = 1/120 + 1/60 + 1/40. Then, calculate the total current using Ohm's Law, I = V/Rt. Finally, use the current divider rule to find the current passing through the 40 ohm resistor.
If they're in parallel, then each resistor acts as if it were the only one,and the presence of any others is irrelevant.The current through the 60-ohm resistor is I = E/R = (120/60) = 2 amperes.
6
If they're in parallel, then the resistors have no effect on each other. The current through each one is the same as it would be if the others were not there at all. The current through the 120Ω resistor is 120 volts/120Ω = 1 Ampere. The 60Ω and the 40Ω are red herring resistors.
To find the current running through the circuit, you need to use Ohm's Law, which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. You can use the following formula to calculate the current: I = V / R Where I is the current, V is the voltage, and R is the resistance. In this case, the total resistance of the circuit is the sum of the individual resistances, which is 5 ohms + 20 ohms + 25 ohms = 50 ohms. Therefore, the current flowing through the circuit is: I = 100 volts / 50 ohms = 2 amps.
Three
The current through the 40-ohm resistor is ( E / R ) = (120 / 40) = 3 amperes.The current through the 40-ohm resistor doesn't depend on the 120-ohm resistor. It's the samewhether the 120-ohm is there or not. It would also be the same if there were any other resistor,with any other resistance, connected in place of the 120-ohm resistor. It would also be the sameif there were 3,000 more resistors in parallel, with all different values of resistance (as long asthe whole conglomeration didn't exceed the capabilities of the power source).
I'm having some trouble focusing in on the schematic of the circuit.