In the x86 processor architecture, memory addresses are specified in two parts called the segment and the offset. One usually thinks of the segment as specifying the beginning of a block of memory allocated by the system and the offset as an index into it. Segment values are stored in the segment registers. There are four or more segment registers: CS contains the segment of the current instruction (IP is the offset), SS contains the stack segment (SP is the offset), DS is the segment used by default for most data operations, ES (and, in more recent processors, FS and GS) is an extra segment register. Most memory operations accept a segment override prefix that allows use of a segment register other than the default one.
If the line segment is 1 inch shorter than the other line segment in Hopeton, then the length of the line segment would be 1 inch less than the length of the other line segment. So, if the other line segment is x inches long, then this line segment would be x - 1 inches long.
Congruent line segment
No it can't because a line segment is a line that is straight. So it is not a line segment.
Yes. A line segment is a line with two points at both ends of it.
Yes, a line segment is a part of a line. A line extends infinitely in two directions, whereas a line segment is a finite portion of that line with two distinct endpoints.
There are four base registers in the 8086/8088; Code Segment (CS), Data Segment (DS), Stack Segment (SS), and Extra Segment (ES).
Give the effective address if the segment register is AA03 and the offset register is 0200.
stack segment
there are 14 registers in 8088 micro processor. All the 14 are 16 bit registers. They are4 segment registers viz - code segment register, stack segment register, data segment register, extra segment register.general registers are - accumulator register i.e. AX, base register i.e. BX, count register i.e. CX, data register i.e. DX and stack pointer (SP), base pointer (BP).index registers are - source index(SI), destination index(DI),and the other registers are instruction pointer and flags register.
SS
8086 has memory divided into segments.Each segment has its particular register like ES, DS, SS, CD (extra segment, data segment, stack segment and code segment).These registers hold the base address BA.Now, there two base registers(BX and BP) and two index registers(SI and DI) in 8086. These registers hols the effective address EA.Now Physical address PA is sum of EA and BA.That is,PA = BA+EA
There are four segment registers on the 8086 and 8088. These are CS (code for code), DS (data segment), ES (extra data segment), and SS (stack segment).
ES
There are four segment registers in the 8086/8088, Code Segment (CS), Stack Segment (SS), Data Segment (DS), and Extra Segment (ES). As a result, there are four segments that can be directly addressed at a particular time, i.e. without an extra instruction to reload a segment register.
There exists 4 general purpose registers in 8086 namely Ax(Accumulator),Bx(Base), Cx(Count), Dx(Data).Further these 4 registers are divided into 8 based on higher and lower bits i.e.,. AX- AH &AL, BX-BH & BL, CX- CH & CL, DX- DH& DL. In 8086, there are 4 segment registers: 1. Stack segment 2. Code segment 3. Data segment 4. Extra segment
DI: ES SI: DS BX: DS
The 16 bit segment register is left shifted by 4 and added to the effective address to form a 20 bit physical address.