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3 piles of blocks: x, y & z Equations: Equ.1: x + y + z = 14 (Total number of blocks = 14) Equ.2: x = z-1 (First pile has one less than the third one) Equ.3: z = 2y Rearrange: y = z/2 (Third pile has twice as many as second one) Substitute the equations 2 & 3 into equation 1, gives us: Equ.4: (z-1) + (z/2) + z = 14 Expand brackets to get: 5z/2 = 15 Rearrange to get: z = (2 x 15)/5 Thus: z = 6 and: y = (z/2) = 6/2 = 3 and: x = (z-1) = 6-1 = 5

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