it depends on how big the files are. for example a picture could be 200Kb. 1000Kb is 1MB, so 44MB = 44,000KBs. if each picture is 200KB then its simple maths. 44,000/200 = 220 pictures. if the pictures were 1mb each in size then 44mb of space would hold 44 pictures. if they were 4kb each, it would hold 11,000 pictures etc. :)
it depends on how big the files are. for example a picture could be 200Kb. 1000Kb is 1MB, so 44MB = 44,000KBs. if each picture is 200KB then its simple maths. 44,000/200 = 220 pictures. if the pictures were 1mb each in size then 44mb of space would hold 44 pictures. if they were 4kb each, it would hold 11,000 pictures etc. :)
With the assumption that each picture taken by the camera is 4 Mb, 32 Mb of memory can save a few pictures. It can only save 8 pictures.
Depends on the Type of Image Format you are using to click the pictures !! If you are clicking pictures from phone that too from a 5 MP camera, it can hold on 200+ pictures !!
Approx. 55 pictures. Varies by camera slightly.
It depends on the size of the pictures. It can hold over a hundred pictures if the pictures are smaller than 150 kb. A 100kb picture size: 550 x 349 - 100k - jpg
60000
A high quality image (1028x768) is about 800-900 KB. A MB is 1000 KB, and a GB is 1000 MB. I would say over 10000 pictures.
Approx 64 pics
No, a 4MB flash drive will only hold about two average sized pictures. Documents vary in size a by huge amounts so it is hard to tell but it would probably not hold more than 20 documents. A 4GB flash drive(there is an enormous difference between megabyte and gigabyte) will hold about 2000 average sized pictures though.
It depends on the format. In JPEG, it's around 18.
Well first that must be a lot of many and Think of it this way, It will hold up to 1000 hours worth of video or about 200,000 songs or a combination of the two. i hope this helped
Is this a trick question? Assuming that only integral number of pictures can be put on the CD, you can put 0 pictures, since the CD isn't big enough to hold even one picture.