2 S2O32- + I2 --> S4O62- + 2 I-
thiosulfate + iodine -> tetrathionate* + iodide
* -O3=-=S-S-S-S=-=O3-
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The product of the reaction between thiosulfate ions and iodine is tetrathionate ions and iodide ions.
When sodium thiosulfate is added to an iodine solution, a reaction occurs where iodine is reduced to iodide ions by thiosulfate, causing the blue color to disappear. This is due to the formation of a colorless complex between iodine and thiosulfate, resulting in a color change.
To neutralize iodine solutions, you can add a reducing agent such as sodium thiosulfate or sodium bisulfite. These chemicals will react with the iodine to form iodide ions, reducing the concentration of free iodine in the solution. It is important to carefully follow established laboratory protocols and safety measures when handling these chemicals.
When potassium and iodine react, they form potassium iodide. The ions involved are K+ (potassium ion) and I- (iodide ion).
Potassium and sodium thiosulfate can turn yellow due to the formation of a colored complex with iodine. When iodine is added to a solution containing thiosulfate, it forms a triiodide ion which has a yellow color. This reaction is commonly used in chemistry as an indicator for the presence of thiosulfate ions in solution.
Yes, sodium thiosulfate can react with silver chloride to form a complex, but it is not a direct chemical reaction. When sodium thiosulfate is added to a solution containing silver chloride, the thiosulfate ions can complex with the silver ions liberated from the silver chloride, forming a soluble complex called a coordination compound.