Ag+ + I- --> AgI
The net ionic equation for the reaction between sodium acetate (NaC2H3O2) and silver nitrate (AgNO3) is: CH3COONa(aq) + AgNO3(aq) → AgCH3COO(s) + NaNO3(aq)
The net ionic equation for the reaction between sodium acetate (NaCH3COO) and silver nitrate (AgNO3) is: CH3COO- + Ag+ -> AgCH3COO. This simplified equation highlights the formation of a precipitate of silver acetate (AgCH3COO) when silver ions (Ag+) react with acetate ions (CH3COO-).
The net ionic equation for sodium acetate (NaC2H3O2) and barium sulfide (BaS) is: Ba2+(aq) + 2CH3COO-(aq) -> Ba(CH3COO)2(s) This equation shows the formation of insoluble barium acetate precipitate.
* NaI + AgNO3 = AgI(s) + NaNO3* CH3COONa + AgNO3 ----------CH3COOAg + NaNO3These reagents doesn't react.* 2 Na3PO4 + 3 BaCl2 = 6 NaCl + Ba3(PO4)2(s)* Na2SO4 + BaCl2 = 2 NaCl + BaSO4(s)
Silver nitrate doesn't react with nitric acid.
The net ionic equation for aluminum bromide and silver acetate is: Al^3+ + 3Br^- + 3Ag^+ + 3C2H3O2^- -> 3AgBr + Al^3+ + 3C2H3O2^-
The net ionic equation for the reaction between sodium acetate (NaC2H3O2) and silver nitrate (AgNO3) is: CH3COONa(aq) + AgNO3(aq) → AgCH3COO(s) + NaNO3(aq)
The net ionic equation for the reaction between sodium acetate (NaCH3COO) and silver nitrate (AgNO3) is: CH3COO- + Ag+ -> AgCH3COO. This simplified equation highlights the formation of a precipitate of silver acetate (AgCH3COO) when silver ions (Ag+) react with acetate ions (CH3COO-).
The net ionic equation for sodium acetate (NaC2H3O2) and barium sulfide (BaS) is: Ba2+(aq) + 2CH3COO-(aq) -> Ba(CH3COO)2(s) This equation shows the formation of insoluble barium acetate precipitate.
The net ionic equation for the reaction between sodium acetate (NaCH₃COO) and barium hydroxide (Ba(OH)₂) is: CH₃COO⁻(aq) + Ba²⁺(aq) → Ba(CH₃COO)₂(s) Sodium ions and hydroxide ions do not participate in the formation of the precipitation of barium acetate, so they are not included in the net ionic equation.
The net ionic equation for sodium acetate (NaCH3COO) and potassium nitrate (KNO3) is: CH3COO^- + K^+ -> KCH3COO
The net ionic equation for the reaction of potassium chloride and lead (II) acetate is: Pb^2+ (aq) + 2Cl^- (aq) -> PbCl2 (s)
Na+(aq) + C2H3O2-(aq) + Ag+(aq) + Cl-(aq) → Na+(aq) + C2H3O2-(aq) + AgCl(s) This net ionic equation represents the reaction between sodium chloride and silver acetate, forming sodium acetate and silver chloride.
there is no net ionic equation. theoretically, there would be a double replacement reaction: 2KBr (aq) + Ca(C2H3O2)2 (aq) --> CaBr2 (aq) + 2KC2H3O2 (aq) however, CaBr2 and KC2H3O2 are both soluble. net ionic equations include only the species that undergo change in an aqueous solution. since all the ions start out as being dissolved in solution, and all the ions end as being dissolved in solution, no ions undergo change, and there is not net ionic equation.
* NaI + AgNO3 = AgI(s) + NaNO3* CH3COONa + AgNO3 ----------CH3COOAg + NaNO3These reagents doesn't react.* 2 Na3PO4 + 3 BaCl2 = 6 NaCl + Ba3(PO4)2(s)* Na2SO4 + BaCl2 = 2 NaCl + BaSO4(s)
Silver nitrate doesn't react with nitric acid.
Balanced equation: Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa Net ionic equation: Cu^2+ + CO3^2- -> CuCO3