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What is an ionic formula for Mg and Br?
The ionic formula for Mg and Br is MgBr2, with magnesium having a 2+ charge and bromine having a 1- charge. MgBr2 indicates that two bromide ions combine with one magnesium ion in the compound.
How many ions does MgBr2 have?
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
How many anions are there in 3.50 g of MgBr2?
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
How many anions are there in 2.50 g of MgBr2?
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
What is the correct name for MgBr2?
Magnesium bromide
Formula for magnesium bromide?
The chemical formula of magnesium dibromide is MgBr2.
What is magnesium bromide?
Formula: MgBr2
What is formula for managanese bromide?
MgBr2
What is the chemical formula for magnesiumbromide?
MgBr2.
What is the chemical formula for magnesium- bromide?
The chemical formula for magnesium bromide is MgBr2. This compound is composed of one magnesium ion (Mg2+) and two bromide ions (Br-).
What is the chemical formula for the compound formed between magnesium and bromine?
2Mg + Br2 ---> 2MgBr Magnesium Bromide
What does the chemical formula MgBr2 stand for?
magnesium bromide
What is an ionic formula for Mg and Br?
The ionic formula for Mg and Br is MgBr2, with magnesium having a 2+ charge and bromine having a 1- charge. MgBr2 indicates that two bromide ions combine with one magnesium ion in the compound.
What is the molecular formula of the product of magnesium reacting with bromine?
*MgBr2
What is the correct chemical formula for magnesuim bromide?
MgBr MgBr2
How many moles are equivalent to 3.6x1024 formula units of MgBr2?
The answer is 5,978 moles.
What is the empirical formula for 13 percent magnesium and 87 percent bromine?
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.
