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What is an ionic formula for Mg and Br?
The ionic formula for Mg and Br is MgBr2, with magnesium having a 2+ charge and bromine having a 1- charge. MgBr2 indicates that two bromide ions combine with one magnesium ion in the compound.
How many ions does MgBr2 have?
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
How many anions are there in 3.50 g of MgBr2?
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
How many anions are there in 2.50 g of MgBr2?
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
What is the correct name for MgBr2?
The correct name for MgBr2 is magnesium bromide.
