Wiki User
∙ 12y agoacid is hbr and the base is h2o
Wiki User
∙ 12y agoIn the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
When hydrogen bromide (HBr) reacts with sodium hydroxide (NaOH), the products formed are sodium bromide (NaBr) and water (H2O). The balanced chemical equation for this reaction is: HBr + NaOH -> NaBr + H2O.
Bromine reacts with water to form hypobromous acid (HOBr) and hydrobromic acid (HBr). The reaction is: Br2 + H2O → HOBr + HBr
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
When hydrobromic acid (HBr) is neutralized with potassium hydroxide (KOH), the salt potassium bromide (KBr) is formed along with water.
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
When hydrogen bromide (HBr) reacts with sodium hydroxide (NaOH), the products formed are sodium bromide (NaBr) and water (H2O). The balanced chemical equation for this reaction is: HBr + NaOH -> NaBr + H2O.
Bromine reacts with water to form hypobromous acid (HOBr) and hydrobromic acid (HBr). The reaction is: Br2 + H2O → HOBr + HBr
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
When bromine reacts with water, it forms hydrobromic acid (HBr) and hypobromous acid (HOBr). The overall reaction can be represented as: Br2 + H2O → HBr + HOBr. This reaction is reversible and depends on the pH and conditions of the solution.
When hydrobromic acid (HBr) is neutralized with potassium hydroxide (KOH), the salt potassium bromide (KBr) is formed along with water.
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
Hydrobromic acid, also known as hydrogen bromide, is a strong acid that dissociates in water to form hydronium ions (H3O+) and bromide ions (Br-). The reaction is represented by the equation: HBr + H2O ⇌ H3O+ + Br-
This equation is:HBr + LiOH = LiBr + H2O
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
The balanced chemical equation for the reaction between NaOH (sodium hydroxide) and HCl (hydrochloric acid) is: NaOH + HCl -> NaCl + H2O In this reaction, sodium hydroxide reacts with hydrochloric acid to form sodium chloride and water.
The neutralization reaction between HBr (hydrobromic acid) and Sr(OH)2 (strontium hydroxide) produces water (H2O) and strontium bromide (SrBr2) as products. The balanced chemical equation for this reaction is 2HBr + Sr(OH)2 → 2H2O + SrBr2.
Hydrobromic acid (HBr) can be derived from hydrogen bromide (H2O) through dissolution in water. When hydrogen bromide is dissolved in water, it forms hydrobromic acid due to the reaction: H2O + HBr → H3O+ + Br-.