acid is hbr and the base is h2o
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
Bromine reacts with water to form a mixture of Hydrobromic Acid, HBr, and Hypobromous Acid, HBrO.
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
The reaction is:HBr + KOH = KBr + H2O
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
Bromine reacts with water to form a mixture of Hydrobromic Acid, HBr, and Hypobromous Acid, HBrO.
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
When bromine reacts with water, it forms hydrobromic acid (HBr) and hypobromous acid (HOBr). The overall reaction can be represented as: Br2 + H2O → HBr + HOBr. This reaction is reversible and depends on the pH and conditions of the solution.
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
The reaction is:HBr + KOH = KBr + H2O
HBr + H2O ----> H3O+ + Br-According to the Brownsted-Lowry definition, acidsare substances that donate H+ ions and bases are substances that accept H+ ions. The HBr gives away a H+ to the H2O making it Hydronium (H3O+), so that makes the HBr an acid and the H2O a base.
This equation is:HBr + LiOH = LiBr + H2O
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
The balanced chemical equation for the reaction between NaOH (sodium hydroxide) and HCl (hydrochloric acid) is: NaOH + HCl -> NaCl + H2O In this reaction, sodium hydroxide reacts with hydrochloric acid to form sodium chloride and water.
Hydrobromic acid (HBr) can be derived from hydrogen bromide (H2O) through dissolution in water. When hydrogen bromide is dissolved in water, it forms hydrobromic acid due to the reaction: H2O + HBr → H3O+ + Br-.
CaCO3 plus HBr would undergo a double displacement reaction, forming calcium bromide (CaBr2) and carbonic acid (H2CO3). Carbonic acid will quickly decompose to form water (H2O) and carbon dioxide (CO2) gas.