Sodium bromide(NaBr) is formed
Yes, bromine reacts with sodium to form sodium bromide. This reaction is a displacement reaction where bromine replaces another element in a compound.
Yes: Bromine reacts with sodium to form sodium bromide.
When sodium reacts with bromine, they form sodium bromide. This is a redox reaction where sodium loses an electron to bromine, which gains an electron to form the bromide ion. The reaction is highly exothermic and can be violent if not controlled.
The yellow color seen when sodium bromide reacts with chlorine is due to the formation of bromine, a reddish-brown liquid, which is a byproduct of the reaction. Bromine is responsible for the yellow color of the solution.
When 1-butene reacts with bromine, an addition reaction occurs where the bromine molecule adds across the double bond of the 1-butene molecule, resulting in the formation of 1,2-dibromobutane.
Yes, bromine reacts with sodium to form sodium bromide. This reaction is a displacement reaction where bromine replaces another element in a compound.
Yes: Bromine reacts with sodium to form sodium bromide.
When sodium reacts with bromine, they form sodium bromide. This is a redox reaction where sodium loses an electron to bromine, which gains an electron to form the bromide ion. The reaction is highly exothermic and can be violent if not controlled.
The yellow color seen when sodium bromide reacts with chlorine is due to the formation of bromine, a reddish-brown liquid, which is a byproduct of the reaction. Bromine is responsible for the yellow color of the solution.
When bromine and sodium combine, they react to form sodium bromide. This is a salt that is water soluble and a common source of bromine in various chemical applications. The reaction between bromine and sodium is a redox reaction where sodium loses an electron to bromine.
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Bromine is an element and can't be "made" from any other element (except by a nuclear reaction). However, since the question asks for a sodium compound, one possibility is sodium bromide, which can be melted and electrolyzed to form bromine at the anode.
When bromine reacts with sodium thiosulfate, the bromine will oxidize the thiosulfate ion to form sulfate ions and release bromide ions. This reaction can be used as a redox titration method to determine the concentration of bromine in a solution.
The sodium methoxide reacts with the water to produce sodium hydroxide an methanol.
When bromine reacts with sodium thiosulfate, it undergoes a redox reaction where bromine is reduced to bromide ions and thiosulfate is oxidized to form sulfate ions. The reaction can be used to titrate bromine in solution, as thiosulfate acts as a reducing agent, consuming the bromine until all the thiosulfate is oxidized.
When 1-butene reacts with bromine, an addition reaction occurs where the bromine molecule adds across the double bond of the 1-butene molecule, resulting in the formation of 1,2-dibromobutane.
The reaction belongs to a class called "single displacement" reactions. In this particular reaction, fluorine replaces the less electronegative bromine in the salt to produce free bromine and sodium fluoride according to the chemical equation: 2 NaBr + F2 -> 2 NaF + Br2.