Ionic bond
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A ionic bond will form between potassium and fluorine. Potassium will donate an electron to fluorine, resulting in the formation of K+ and F- ions, which will be attracted to each other due to their opposite charges.
An ionic bond would form between fluorine and potassium. Fluorine has a high electronegativity and would attract the electron from potassium, leading to the transfer of electrons and the formation of ions, resulting in an ionic bond between the two elements.
Ionic bond, because fluorine is electronegative compared to potassium. Fluorine will transfer an electron to potassium, resulting in the formation of ions with opposite charges that are attracted to each other.
To draw the ionic bond between potassium and fluorine, you would represent potassium (K) as donating an electron to fluorine (F). Fluorine would then become a fluoride ion with a negative charge (F-), while potassium would become a potassium ion with a positive charge (K+). Draw them with square brackets denoting their charges and an arrow pointing from K to F to show the transfer of electrons.
Yes, potassium fluoride (KF) forms an ionic bond. Potassium (K) is a metal and fluorine (F) is a nonmetal, resulting in the transfer of electrons from potassium to fluorine to form K+ and F- ions, which are held together by electrostatic forces.
KF is an ionic bond because it is a combination of a metal (potassium) and a non-metal (fluorine), resulting in the transfer of electrons from potassium to fluorine. This transfer creates ions in which potassium becomes K+ and fluorine becomes F-.