CaF2
Calcium fluoride
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An ionic bond between F (fluorine) and Ca (calcium) would form when fluorine gains an electron to achieve a stable octet configuration and becomes a fluoride ion (F-), while calcium loses two electrons to become a calcium ion (Ca2+). The attraction between the oppositely charged ions leads to the formation of calcium fluoride (CaF2) crystal lattice.
An ionic bond would form between fluorine and potassium. Fluorine has a high electronegativity and would attract the electron from potassium, leading to the transfer of electrons and the formation of ions, resulting in an ionic bond between the two elements.
No, potassium (K) and bromine (Br) would not form an ionic bond. Both elements already have full outer electron shells, so they are stable and unlikely to form an ionic bond with each other.
Ionic bonds typically form between a metal and a nonmetal, while covalent bonds form between two nonmetals. Without knowing the elements represented by "CB," it is difficult to determine if the bond would be ionic or covalent.
Ionic bond would form between Na and Cl. In this bond, sodium (Na) will transfer an electron to chlorine (Cl) to achieve a stable electron configuration. This results in the formation of Na+ cation and Cl- anion, which are attracted to each other due to their opposite charges, forming an ionic bond.
Yes, zinc and chlorine can form an ionic bond. Zinc loses two electrons to form a 2+ cation, while chlorine gains one electron to form a 1- anion. The attraction between the opposite charges results in the formation of an ionic bond between zinc and chlorine.