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How would you prepare 500 mL of a 1M solution of acetic acid -HC2H3O2- from a stock solution of 6M of acetic acid?
Broah
C1V1 = C2V2
(500ml)(1M) = (Xml)(6M) ( divide both sides by 6 in this case )
= 83.3ml
Put this 83.3ml of 6M acid into a 600ml beaker and add 416.7ml to get 500ml total.
Wiki User
∙ 14y ago
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.
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What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare?
To prepare 500 mL of a 0.5 M solution of acetic acid, you would need to take 100 mL of the 2.5 M stock solution and dilute it to 500 mL. This is because the molarity equation (M1V1 = M2V2) can be used to calculate the volume of stock solution needed for dilution.
What volume of 2.5 m stock solution of acetic acid hc2h3o2 is required to prepare 100 mll of a .50 m acetic acid solution?
To prepare a 0.5 M acetic acid solution using a 2.5 M stock solution, you will need to dilute it. The formula for dilution is C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you will need 20 ml of the 2.5 M stock solution to make 100 ml of a 0.5 M acetic acid solution.
What volume of a 2.5M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50M acetic acid solution?
To prepare the 0.50M acetic acid solution, you can use the formula C1V1 = C2V2. Plugging in the values, you get (2.5M)(V1) = (0.50M)(100.0mL). Solving for V1 gives V1 = 20.0 mL. Therefore, 20.0 milliliters of the 2.5M stock solution is required to prepare 100.0 milliliters of the 0.50M acetic acid solution.
What volume of a 2.5 M stock solution of acetic acid (HCHÀO) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
To prepare a 0.50 M acetic acid solution, you would need to dilute the 2.5 M stock solution. By using the formula M1V1 = M2V2, you can calculate the volume of the stock solution needed as: (0.5 M)(100.0 mL) = (2.5 M)(V2), where V2 is the volume of the stock solution needed. So, V2 = (0.5 M x 100.0 mL) / 2.5 M = 20.0 mL. Therefore, you would need 20.0 mL of the 2.5 M stock solution to prepare the desired 100.0 mL of 0.50 M acetic acid solution.
What volume of a 2.5 M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
To determine the volume of the 2.5 M stock solution needed, you can use the dilution formula: M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume. Rearrange the formula to solve for V1, which is the volume of the stock solution you need to prepare 100.0 milliliters of a 0.50 M solution. Substituting the values gives: V1 = (0.50 M * 100.0 mL) / 2.5 M = 20.0 milliliters. Therefore, you need 20.0 milliliters of the 2.5 M stock solution to prepare 100.0 milliliters of the 0.50 M solution.
What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare?
To prepare 500 mL of a 0.5 M solution of acetic acid, you would need to take 100 mL of the 2.5 M stock solution and dilute it to 500 mL. This is because the molarity equation (M1V1 = M2V2) can be used to calculate the volume of stock solution needed for dilution.
What volume of 2.5 m stock solution of acetic acid hc2h3o2 is required to prepare 100 mll of a .50 m acetic acid solution?
To prepare a 0.5 M acetic acid solution using a 2.5 M stock solution, you will need to dilute it. The formula for dilution is C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you will need 20 ml of the 2.5 M stock solution to make 100 ml of a 0.5 M acetic acid solution.
What volume of a 2.5M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50M acetic acid solution?
To prepare the 0.50M acetic acid solution, you can use the formula C1V1 = C2V2. Plugging in the values, you get (2.5M)(V1) = (0.50M)(100.0mL). Solving for V1 gives V1 = 20.0 mL. Therefore, 20.0 milliliters of the 2.5M stock solution is required to prepare 100.0 milliliters of the 0.50M acetic acid solution.
What volume of a 2.5 M stock solution of acetic acid (HCHÀO) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
To prepare a 0.50 M acetic acid solution, you would need to dilute the 2.5 M stock solution. By using the formula M1V1 = M2V2, you can calculate the volume of the stock solution needed as: (0.5 M)(100.0 mL) = (2.5 M)(V2), where V2 is the volume of the stock solution needed. So, V2 = (0.5 M x 100.0 mL) / 2.5 M = 20.0 mL. Therefore, you would need 20.0 mL of the 2.5 M stock solution to prepare the desired 100.0 mL of 0.50 M acetic acid solution.
Prepare a working solution from a stock solution?
To prepare a working solution from a stock solution, you need to dilute the stock solution with a suitable solvent (such as water or buffer) to achieve the desired concentration. The equation C1V1 = C2V2 can help you calculate the volume of stock solution (V1) needed to make the desired volume of working solution (V2) at the desired concentration (C2). Always remember to mix the solutions thoroughly after dilution.
What volume of a 2.5 M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
To determine the volume of the 2.5 M stock solution needed, you can use the dilution formula: M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume. Rearrange the formula to solve for V1, which is the volume of the stock solution you need to prepare 100.0 milliliters of a 0.50 M solution. Substituting the values gives: V1 = (0.50 M * 100.0 mL) / 2.5 M = 20.0 milliliters. Therefore, you need 20.0 milliliters of the 2.5 M stock solution to prepare 100.0 milliliters of the 0.50 M solution.
You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml?
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
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