0.2 N HCl solution means 0.2 equivalents of HCl dissolved in 1 litre of water.
Normality = Molarity x n-factor
=> Molarity =Normality/n-factor=0.2/1=0.2 M
0.2 moles should be present in 1 litre of solution.
0.2moles =0.2 x 36.5 = 7.3 grams of HCl
=>Dissolve 7.3 grams of HCl in 1 litre if water to get a 0.2N solution.
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To prepare a 0.2N HCl solution, you would need to dilute concentrated hydrochloric acid with water. Measure out the required volume of concentrated HCl (around 3.65 mL of concentrated HCl in 1 liter of solution) and dilute it with water to make a total volume of 1 liter. Be sure to wear appropriate PPE and handle the acid with care.
To prepare a 0.2N HCl solution from 1.0N HCl, you can dilute the 1.0N HCl solution by adding 4 parts of water to 1 part of the 1.0N HCl solution. This means combining 1 volume of 1.0N HCl with 4 volumes of water to obtain the desired 0.2N HCl solution.
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
To prepare 1M Tris-HCl from a 10mM solution, you would need to dilute the 10mM solution by a factor of 100. This means you would mix 1 part of the 10mM solution with 99 parts of water to achieve a final concentration of 1M Tris-HCl.
To prepare 1 liter of 0.1N HCl solution from 12N HCl, you would need to dilute the 12N HCl by a factor of 120. To do this, you would add approximately 83.33 mL of 12N HCl to a container and then dilute it with water to reach a final volume of 1 liter. Make sure to mix the solution thoroughly after dilution.
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.