2.11 x 10^22
This is how you figure it out:
3.78g divided by 107.87(the Atomic Mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.
In one molecule of silver iodide (AgI), there is one silver atom and one iodine atom, totaling two atoms.
There are a total of 17 atoms in one molecule of silver chromate (Ag2CrO4). This includes 2 silver atoms, 1 chromium atom, 4 oxygen atoms, totaling 7 atoms for each repeating unit in the compound.
The number of silver atoms in a piece of jewelry would depend on the size and weight of the jewelry. A typical piece of silver jewelry may contain millions to billions of silver atoms.
Silver is an element, pure silver would contain only silver atoms.
To calculate the number of silver atoms in 3.76g of silver, you need to use Avogadro's number and the molar mass of silver. The molar mass of silver is 107.87 g/mol. First, calculate the number of moles in 3.76g of silver. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of silver atoms in that many moles.
Talon of the Silver Hawk has 378 pages.
Silver is an atom.
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A mole of silver contains approximately 6.022 x 10^23 atoms.
There are 6.022x1023 atoms in a mole. You multiply 6.022x1023 by 8.68, which equals 52.20796x1023 atoms
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
There are 5 atoms in silver nitrate (1 silver, 1 nitrogen and 3 oxygens).
2.17*10^22
2.26*1024
5 :)
In one molecule of silver iodide (AgI), there is one silver atom and one iodine atom, totaling two atoms.
There are a total of 17 atoms in one molecule of silver chromate (Ag2CrO4). This includes 2 silver atoms, 1 chromium atom, 4 oxygen atoms, totaling 7 atoms for each repeating unit in the compound.