2.11 x 10^22
This is how you figure it out:
3.78g divided by 107.87(the Atomic Mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.
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To find the number of silver atoms in 3.78g of silver, first calculate the molar mass of silver (Ag) which is 107.87 g/mol. Next, convert 3.78g of silver to moles by dividing by the molar mass. Finally, use Avogadro's number (6.022 x 10^23) to find the number of atoms, which will be approximately 6.61 x 10^22 atoms.
In one molecule of silver iodide (AgI), there is one silver atom and one iodine atom, totaling two atoms.
There are a total of 17 atoms in one molecule of silver chromate (Ag2CrO4). This includes 2 silver atoms, 1 chromium atom, 4 oxygen atoms, totaling 7 atoms for each repeating unit in the compound.
The number of silver atoms in a piece of jewelry would depend on the size and weight of the jewelry. A typical piece of silver jewelry may contain millions to billions of silver atoms.
There is only one type of atom in silver, which is the element silver itself. Silver atoms are composed of 47 protons and are identified by the atomic number 47 on the periodic table.
Ag2CO3 contains 6 elements (silver, carbon, and oxygen) and a total of 9 atoms (2 silver atoms, 1 carbon atom, and 3 oxygen atoms).