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The balanced equation for the reaction between Iodine and Hydrogen is:

H2 + I2 --> 2HI

The ratio of I2 to HI is 1:2

Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide

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When 1 mole of iodine reacts with excess hydrogen according to the balanced equation: I2 + H2 → 2HI, 1 mole of hydrogen iodide (HI) is produced.

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Q: How many moles of hydrogen iodide are produced from 1 mole of iodine?
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