Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
If 0.36 moles of zinc reacts with an equal amount of H2SO4, then the stoichiometry of the reaction tells us that for every 1 mole of zinc, 1 mole of hydrogen gas is produced. Therefore, 0.36 moles of hydrogen gas will be produced.
The mole ratio of hydrogen to ammonia in the reaction is 3:2. This means that for every 3 moles of hydrogen that react, 2 moles of ammonia are produced.
To find the number of grams in 0.02 moles of beryllium iodide (BeI2), you would first calculate the molar mass of BeI2, which is 262.83 g/mol. Then, you would multiply the molar mass by the number of moles: 0.02 moles * 262.83 g/mol = 5.26 grams of beryllium iodide.
To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
The balanced chemical equation for the reaction between chlorine and iodine is 1:1. This means that for every mole of chlorine consumed, one mole of iodine is produced. Therefore, from 8.00 moles of chlorine, 8.00 moles of iodine are produced.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol β 91.4 grams of iodine are produced.
Ammonia is produced from the reaction of hydrogen and nitrogen in a 3:1 ratio. Therefore, 12.0 moles of hydrogen will produce 4.0 moles of ammonia.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
In the balanced chemical equation 2H2 + O2 -> 2H2O, it states that 2 moles of hydrogen form 2 moles of water. Since 2.5 moles of hydrogen are reacting, you can calculate the amount of water produced by multiplying the number of moles of hydrogen by the ratio in the balanced equation. Therefore, 2.5 moles of hydrogen will produce 2.5 moles of water.
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How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
If 0.36 moles of zinc reacts with an equal amount of H2SO4, then the stoichiometry of the reaction tells us that for every 1 mole of zinc, 1 mole of hydrogen gas is produced. Therefore, 0.36 moles of hydrogen gas will be produced.
10,55 moles of water are obtained.
6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water. Cheers!
The mole ratio of hydrogen to ammonia in the reaction is 3:2. This means that for every 3 moles of hydrogen that react, 2 moles of ammonia are produced.