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divide the mass by molar mass. Molar mass of NH3 is 17. answer is 0.044mol
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∙ 8y ago
To find the number of moles in 0.75 g of ammonia (NH3), you first need to calculate the molar mass of ammonia (NH3) which is approximately 17 g/mol. Then divide the given mass (0.75 g) by the molar mass to get the number of moles. In this case, 0.75 g of ammonia is equivalent to about 0.044 moles.
Wiki User
∙ 8y agoMolar mass of ammonia is 17 g. Hence 0.75 g of ammonia will contain 0.044 moles of ammonia.
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How many moles are in 12 x 10.3 grams of ammonia NH3?
To find the number of moles in 12 x 10.3 grams of ammonia (NH3), you first need to calculate the molar mass of NH3 (17.03 g/mol). Then divide the given mass (12 x 10.3 g) by the molar mass to get the number of moles, which should be approximately 72 moles.
How many moles of hydrogen are in 6.50 g of ammonia?
To find the number of moles of hydrogen in 6.50 g of ammonia (NH3), first calculate the molar mass of ammonia (17.03 g/mol). Since ammonia has 3 hydrogen atoms, each with a molar mass of 1.01 g/mol, one mole of ammonia contains 3 moles of hydrogen atoms. Therefore, 6.50 g of ammonia contains (6.50 g / 17.03 g/mol) * 3 moles of hydrogen atoms.
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia (NH3) is 17.03 g/mol. Therefore, the mass of 3 moles of ammonia would be 51.09 grams (17.03 g/mol x 3 moles = 51.09 grams).
How many molecules are in .75 g of ammonia?
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
How many moles are in 1.2 X 10.3 grams of ammonia NH2?
To find the number of moles in 1.2 x 10.3 grams of ammonia (NH3), you first need to calculate the molar mass of ammonia: 1 nitrogen atom (N) + 3 hydrogen atoms (H) = 14.01g/mol + (3 x 1.01g/mol) = 17.04g/mol. Next, divide the given mass (12 x 10.3g) by the molar mass to get the number of moles: (1.2 x 10.3g) / 17.04g/mol = 0.709 moles.
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
How many moles are in 12 x 10.3 grams of ammonia NH3?
To find the number of moles in 12 x 10.3 grams of ammonia (NH3), you first need to calculate the molar mass of NH3 (17.03 g/mol). Then divide the given mass (12 x 10.3 g) by the molar mass to get the number of moles, which should be approximately 72 moles.
How many moles of hydrogen are in 6.50 g of ammonia?
To find the number of moles of hydrogen in 6.50 g of ammonia (NH3), first calculate the molar mass of ammonia (17.03 g/mol). Since ammonia has 3 hydrogen atoms, each with a molar mass of 1.01 g/mol, one mole of ammonia contains 3 moles of hydrogen atoms. Therefore, 6.50 g of ammonia contains (6.50 g / 17.03 g/mol) * 3 moles of hydrogen atoms.
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia (NH3) is 17.03 g/mol. Therefore, the mass of 3 moles of ammonia would be 51.09 grams (17.03 g/mol x 3 moles = 51.09 grams).
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many moles are present in 1 g of ammonia?
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
What would be the Mass of 3 moles of ammonia and calculate the number of ammonia molecules?
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
300 g of ammonia react with 36 moles of sulfuric acid to produce ammonia sulfate how many moles of excess sulfuric acid are left over after the reaction is complete?
26.9 - 27.4
How many molecules are in .75 g of ammonia?
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
How many moles of ammonia is 170000g?
To find the number of moles in 170000g of ammonia, you need to first calculate the molar mass of ammonia (NH3), which is approximately 17g/mol. Then, divide the given mass (170000g) by the molar mass to get the number of moles: 170000g / 17g/mol = 10000 moles of ammonia.
How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
