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How many moles are in 12 x 10.3 grams of ammonia NH3?
To find the number of moles in 12 x 10.3 grams of ammonia (NH3), you first need to calculate the molar mass of NH3 (17.03 g/mol). Then divide the given mass (12 x 10.3 g) by the molar mass to get the number of moles, which should be approximately 72 moles.
How many moles of hydrogen are in 6.50 g of ammonia?
To find the number of moles of hydrogen in 6.50 g of ammonia (NH3), first calculate the molar mass of ammonia (17.03 g/mol). Since ammonia has 3 hydrogen atoms, each with a molar mass of 1.01 g/mol, one mole of ammonia contains 3 moles of hydrogen atoms. Therefore, 6.50 g of ammonia contains (6.50 g / 17.03 g/mol) * 3 moles of hydrogen atoms.
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
How many molecules are in .75 g of ammonia?
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
What is the mass of 10 moles of ammonia given that molecular weight is 17?
If ammonia (NH3) has a molar weight of 17 grams per mole, then 10 moles means 17x10=170 grams.
How many moles are present in 1 g of ammonia?
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
How many moles are in 12 x 10.3 grams of ammonia NH3?
To find the number of moles in 12 x 10.3 grams of ammonia (NH3), you first need to calculate the molar mass of NH3 (17.03 g/mol). Then divide the given mass (12 x 10.3 g) by the molar mass to get the number of moles, which should be approximately 72 moles.
How many moles of hydrogen are in 6.50 g of ammonia?
To find the number of moles of hydrogen in 6.50 g of ammonia (NH3), first calculate the molar mass of ammonia (17.03 g/mol). Since ammonia has 3 hydrogen atoms, each with a molar mass of 1.01 g/mol, one mole of ammonia contains 3 moles of hydrogen atoms. Therefore, 6.50 g of ammonia contains (6.50 g / 17.03 g/mol) * 3 moles of hydrogen atoms.
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
How many moles of hydrogen must react to produce 68 grams of ammonia?
To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.
How many moles are present in 1 g of ammonia nh3?
To find the number of moles in 1 g of ammonia (NH₃), first calculate its molar mass. The molar mass of NH₃ is approximately 17 g/mol (14 g/mol for nitrogen and 3 g/mol for hydrogen). Using the formula for moles (moles = mass/molar mass), we can calculate: 1 g NH₃ × (1 mol / 17 g) ≈ 0.059 moles of NH₃.
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
What would be the Mass of 3 moles of ammonia and calculate the number of ammonia molecules?
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
300 g of ammonia react with 36 moles of sulfuric acid to produce ammonia sulfate how many moles of excess sulfuric acid are left over after the reaction is complete?
26.9 - 27.4
How many moles of ammonia is 170000g?
Ammonia = NH3Molecular mass = 16.0Formula of grams to moles: grams / molecular mass = moles170,000 g / (16.0) = 10,600 moles NH3Note that the answer is with three significant digits
