Atomic Weight sodium = 23 so 46/23 = 2 moles of sodium in 46.0g
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To find the number of moles in 46.0 g of sodium, you need to divide the given mass by the molar mass of sodium. The molar mass of sodium (Na) is 22.99 g/mol. Thus, 46.0 g ÷ 22.99 g/mol = 2 moles of sodium.
The molar mass of sodium is 22.99 g/mol. Therefore, the mass of 8 moles of sodium would be 8 moles x 22.99 g/mol = 183.92 g.
To determine the number of moles in 20g of sodium hydroxide, you need to divide the given mass by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). So, 20g NaOH / 40 g/mol = 0.5 moles of sodium hydroxide.
To find the number of moles in 46g of sodium, you need to divide the mass of the sample by the molar mass of sodium (22.99 g/mol). The calculation is 46g / 22.99 g/mol = approximately 2 moles of sodium.
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
To determine the number of moles in 73.5 g of sodium sulfide (Na2S), you first need to calculate the molar mass of Na2S, which is 78.04 g/mol. Then divide the given mass by the molar mass to find the number of moles. Therefore, 73.5 g / 78.04 g/mol = 0.942 moles of sodium sulfide.