answersLogoWhite

0

What else can I help you with?

Related Questions

Which gas turns acidified potasium dichromate solution into green?

Sulfur dioxide gas turns acidified potassium dichromate solution green.


What happens in a positive test for sulfur dioxide?

The aqueous acidified potassium dichromate(VI) solution turns from orange to green.


how can you recover the potassium dichromate from its solution in water?

Potassium dichromate can be recovered from its solution in water by adding a reducing agent, such as sulfur dioxide or sodium bisulfite, to convert the dichromate ions (Cr2O7^2-) to chromium (III) ions (Cr^3+). The chromium (III) can then be precipitated as chromium hydroxide by adjusting the pH of the solution and then separated through filtration.


What gas that passed through into an acidic dichromate solution and turn the solution from orange to green?

Sulfur dioxide gas passed through an acidic dichromate solution turns the solution from orange to green.


How do carbon dioxide and potassium dichromate react?

When carbon dioxide reacts with potassium dichromate in an acidic solution, a color change from orange to green occurs due to the reduction of chromium(VI) to chromium(III) ions. The balanced chemical equation for this reaction is 3CO2 + Cr2O7^2- + 8H^+ -> 3CO2 + 2Cr^3+ + 4H2O.


What happens when you heat glycerol with potassium dichromate?

When you heat glycerol with potassium dichromate, the dichromate ion oxidizes the glycerol to form products including carbon dioxide, water, and potentially other byproducts. This is a common reaction used to demonstrate oxidation of organic compounds in the laboratory.


What is the reaction of acidified pot dichromate with Hydrogen Sulphide?

When acidified potassium dichromate (K2Cr2O7) reacts with hydrogen sulfide (H2S), it forms chromium(III) sulfide (Cr2S3), sulfur dioxide (SO2), and water (H2O). The orange dichromate solution turns green as Cr2S3 is formed. This reaction is often used as a test for the presence of hydrogen sulfide gas.


Sulfuric acid and potassium dichromate in ethanol make?

When sulfuric acid and potassium dichromate react in ethanol, they form chromium(III) sulfate, potassium sulfate, water, and carbon dioxide. This is a redox reaction where the dichromate ion is reduced to chromium(III) while sulfuric acid is acting as a catalyst. The products will vary depending on the specific conditions of the reaction.


How would you test for the presence of sulfur Dioxide?

One common method to test for the presence of sulfur dioxide is using sodium metabisulfite paper strips, which change color in the presence of sulfur dioxide. Another method is using a chemical solution like hydrogen peroxide and hydrochloric acid, which reacts with sulfur dioxide to form a white precipitate of sulfur.


Which gas turns K2Cr2O7 paper from orange to green with chemical equation?

Sulfur dioxide gas turns acidifiedpotassium dichromate(VI) solution from orange to green.Chromium is reducedfrom (VI) to (III). potassium sulfur sulfuric chromium(III) potassiumdichromate(VI) + dioxide + acid sulfate + sulfate + water.


What happens when potassium dichromate reacts with oxalic acid what is the name of the product?

When potassium dichromate reacts with oxalic acid, it undergoes a redox reaction where the dichromate ion is reduced to chromium(III) ion, and the oxalic acid is oxidized to carbon dioxide and water. The products of this reaction are chromium(III) oxide, carbon dioxide, and water.


What is principle of potassium dichromate in COD estimation?

The titer volume of the sample gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the solution. Similarly, the titer volume for the blank (distilled water) gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the blank. The equation for the titration can be expressed as: Cr2O72 -- + FeSO4 (NH4)2SO4 = Cr+ + NH4+ + Fe 3+ From above equation it can be seen that one molecule of dichromate corresponds to one molecule of Mohr's salt. Thus, the difference in volume of excess K2Cr2O7 reacting with Mohr's solution can be calculated from the expression: = (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) solution - (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) blank = (Vol. of K2Cr2O7 used for oxidation) blank - Vol. of K2Cr2O7 used for oxidation) solution Hence, the difference in the titer volume for the solution and the blank is used to find out the Chemical Oxygen Demand directly.