Q: When do you use D2 when driving automatic car?

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That would be the second gear of your automatic transmission.

2nd gear. (the gear you would use from about 15-35mph)

Something that will destroy your car Jk it will allow you to get full power through each gear if you shift up starting from 1 #smooth -Wasaab

D3 will do for almost all driving conditions.D2 and D1 would be for low speed driving when you do not want the trans to shift gears.

When you are driving up a steep upgrade/mountain like I did this weekend going to Brasstown Bald Mountain, GA in a 2003 Honda Civix EX Coupe.

Here~ D2 D2 D2 B D2 C2 B A C2 C2 C2 A C2 B A G D2 D2 D2 G G A B C2 C2 C2 C2 D2 C2 B A G D2 D2 D2 B D2 D2 D2 B D2 D2 D2 E2 D2 D2 B C2 C2 C2 A C2 C2 C2 A C2 C2 C2 B2 C2 B A G

if you have a radius in a circle do you use A=(3.14)d2

d2 and d2 are the same.

Take the D1/E50/E65 and D2/E65 / 407 km - about 3 hours 53 mins.

Terminator Theme ============= C2 D2 D2# ------ D2 A1# D1# ------- C2 D2 D2# ------ D2 A1# G2 F2 ----- C2 D2 D2# ------ D2 A1# F1 --------- D1# --------- C1 D1# D1 -------------

d2 diesel price per gallon

Let D represent the length of the diagonal and A the area. Suppose the sides are L and B. Then A = L*B and by Pythagoras, D2 = L2 + B2 These two equations need to be solved as simultaneous equations to get the values of L and B. One way is to use the following identities: (L + B)2 = L2 + 2LB + B2 = D2 + 2A so that L + B = sqrt(D2 + 2A) and (L - B)2 = L2 - 2LB + B2 = D2 - 2A so that L - B = sqrt(D2 - 2A) which then give 2L = sqrt(D2 + 2A) + sqrt(D2 - 2A) and 2B = sqrt(D2 + 2A) - sqrt(D2 - 2A)