A multimeter.
A multimeter.
If voltage remains constant and resistance is increased, the amperage will decrease per Ohm's Law.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
a. amperage and voltage b. the size and length of the wires c. voltage and resistance d. fuses and circuit breakers
Voltage source: is any source that voltage and amperage come from. Resistor: is any part of a circuit that consumes that energy!
You don't convert DC voltage to DC amperage. You get it automaticly when you have a resistance in your circuit. Scroll down to related links and look at "Ohm's law - Wikipedia".
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
Turn off circuit. Then you can use a meter set for resistance, clip onto both ends of the resistor, meter will display the resistance in ohms.If you know the voltage and amperage you can use Ohm's Law: E=IRR=E/IR is resistance, E is voltage, and I is current (amperage)
You cannot increase amperage without changing voltage or resistance. Ohm's law states that voltage is current times resistance. You cannot change one alone. Not even changing frequency in a capacitive or inductive circuit will do this, because changing frequency represents a change in reactance, which is effectively a change in resistance.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
This doesn't make sense, "current" is "amperage" so the higher the voltage the lower the amperage, and the lower the voltage the higher the amperage.
No, the resistance in a circuit does not change when voltage changes. Resistance is an inherent property of the circuit.