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A multimeter.

Q: What specialty tool can be used to test voltage resistance and amperage in a circuit?

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A multimeter.

If voltage remains constant and resistance is increased, the amperage will decrease per Ohm's Law.

Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R

a. amperage and voltage b. the size and length of the wires c. voltage and resistance d. fuses and circuit breakers

Voltage source: is any source that voltage and amperage come from. Resistor: is any part of a circuit that consumes that energy!

You don't convert DC voltage to DC amperage. You get it automaticly when you have a resistance in your circuit. Scroll down to related links and look at "Ohm's law - Wikipedia".

Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.

To calculate resistance in a circuit, you can use Ohm's Law: resistance (R) equals voltage (V) divided by current (I), or R = V/I. You can also calculate resistance using the color bands on a resistor using a resistor color code chart.

You cannot increase amperage without changing voltage or resistance. Ohm's law states that voltage is current times resistance. You cannot change one alone. Not even changing frequency in a capacitive or inductive circuit will do this, because changing frequency represents a change in reactance, which is effectively a change in resistance.

Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)

This doesn't make sense, "current" is "amperage" so the higher the voltage the lower the amperage, and the lower the voltage the higher the amperage.

No, the resistance in a circuit does not change when voltage changes. Resistance is an inherent property of the circuit.