15m/s divided by 5s = 3m/s^2
The change in velocity, in this case, is equal to acceleration x time.
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
(15 meters) / (5 seconds) = 3 meters per second
v = u + at where u = starting velocity, v = final velocity, a = acceleration, t = time. Here u = 0 so v = at ie a = v/t Now, v = 5 m/s (what is mk?) and t = 5 s So a = (5 m/s) / 5 s = 1 m/s2
v = vo + gt = 2(m/s) + 9.8(m/s2) x 5s = 51(m/s)
It is 5s + 4d.
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.