acceleration = a = (60 - 0)/(9.8)
a = 6.12 mi/hr - sec
a = (6.12 mi/hr - sec)* (1 hour/3600 sec)
a = 0.0017 mi/sec^2
Use the formula
S = VoT + (1/2)(a)(T^2)
S = distance travelled
Vo = initial velocity = 0
T = time travelled = 9.8 sec
a = acceleration = 0.0017 mi/sec^2
S = 0 + (1/2)(0.0017)(9.8^2)
S = 0.0816 mi
S = 0.0816 mi * 5280 feet/mi = 431 feet
Speed = Distance/Time
To find the average speed you must know the total distance traveled and the total elapsed. The distance traveled in each interval is simply the speed multiplied by the time (v x t). Thus, in the first interval you travel 120 x 1 = 120 meters, in the second interval 120 x 6 = 720 meters; therefore, the total distance traveled is 840 meters. The total time elapsed is 120 + 120 = 240 seconds. An average speed is simply the total distance traveled divided by the total time elapsed thus in this case it is 720 m / 240 s = 3 m/s.
No. If you divide a distance by a speed, you get a time, not a speed. For example, (meters) / (meters/second) = (seconds).
No. The total distance traveled divided by constant speed is the time interval.
Total distance traveled / time
the rate of speed
Retention Factor Rf == Distance traveled / total distance