What is the total distance traveled for a car going 0-60 in 9.8 seconds?

Answer 1

acceleration = a = (60 - 0)/(9.8)

a = 6.12 mi/hr - sec

a = (6.12 mi/hr - sec)* (1 hour/3600 sec)

a = 0.0017 mi/sec^2

Use the formula

S = VoT + (1/2)(a)(T^2)

where

S = distance travelled

Vo = initial velocity = 0

T = time travelled = 9.8 sec

a = acceleration = 0.0017 mi/sec^2

Substituting values,

S = 0 + (1/2)(0.0017)(9.8^2)

S = 0.0816 mi

S = 0.0816 mi * 5280 feet/mi = 431 feet