Q: What is the expansion of s u v car?

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Acceleration = (v - u) / t So a = (24 - 6.5) / 3.5*60 a = 1/12 m/s^2 Now to find the displacement S, just use S = (v+u)(v-u) / 2 * a Hope you would do the rest

u=28m/s v=0m/s t=1.8s a=? Solution: v=u+at 0=28+(-a)1.8 -28=-1.8a 28=1.8a a=15.5m/s2

the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory): s = ut + Β½at^2 β¦. (1) v^2 = u^2 + 2as β¦. (2) v = u + at β¦. (3) s = (u + v)t/2 β¦. (4) where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time. In this case, we know u = 10m/s, v = 50m/s, t = 10s and we want to find a, so we use equation (3) v = u + at 50 = 10 + 10t, so t = (50 β 10)/10 = 4m/s^2

Yes. a/b / u/v / r/s = (a*v)/(b*u) / r/s = (a * v * s) / (b * u * r)

Apply to the equation V=U+at . The answer is 40.

The SUVAT equations: s=ut + 1/2at^2 v= u + at v^2 = u^2 + 2as s=1/2(u+v)t s = displacement u= initial velocity v= final velocity a= acceleration t= time

The speed at which the egg will be traveling when it hits the ground depends on various factors such as air resistance and initial velocity. Assuming the egg is in free fall and neglecting air resistance, its speed when it hits the ground can be calculated using the equation (v = \sqrt{2 \cdot g \cdot h}), where (v) is the final velocity, (g) is the acceleration due to gravity (approximately 9.81 m/sΒ²), and (h) is the height (11 meters in this case). This would give a final velocity of approximately 14 m/s.

v2- u 2 = 2assince, S (Distance) = Average speed x TimeS = U+V / 2 * TS = U+V / 2 * V - U / A {since T = V -U / A}S = V2 - U2 / 2A2AS = V2 - U2OR V2 - U2 = AsHence, Derived.

It is spelled s-u-r-v-i-v-e.

acceleration(a) = (final velocity(v) - Initial velocity(u)) / time (s) Algebraically a = (v - u) / t Where 'v' & 'u' are measured in metres per second ( m/s) or ms^-1 And 't' is the time in seconds measured is 's' Hence a(ms^-2) = v(m/s) - u(m/s)) / t(s) And example is a car starting from rest up to 44 m/s ( 30 mph) in 10 seconds. a = (44 - 0 ) / 10 a = 44/10 a = 4.4 ms^-2. NB Earth's gravitational acceleration(g) is approximately 10 ms^-2.

Suppose you have the fractions p/q and r/s. Let the LCM of q and s be t.Then t is a multiple of q as well as of s so let t= q*u and t = s*v Then p/q = (p*u)/(q*u) = (p*u)/t and r/s = (r*v)/(s*v) = (r*v)/t have the same denominators.

v = u + at where u = starting velocity, v = final velocity, a = acceleration, t = time. Here u = 0 so v = at ie a = v/t Now, v = 5 m/s (what is mk?) and t = 5 s So a = (5 m/s) / 5 s = 1 m/s2