What is the expansion of s u v car?

Updated: 4/28/2022
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Q: What is the expansion of s u v car?
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A car enters a freeway with a speed of 6.5 m s and accelerates to sped of 24 m s in 3.5 min how far does the car travel while is accelerating?

Acceleration = (v - u) / t So a = (24 - 6.5) / 3.5*60 a = 1/12 m/s^2 Now to find the displacement S, just use S = (v+u)(v-u) / 2 * a Hope you would do the rest

A car moving 28 m/s skids to avoid an accident, stopping in 1.8 s. calculate the acceleration of the car while it stops?

u=28m/s v=0m/s t=1.8s a=? Solution: v=u+at 0=28+(-a)1.8 -28=-1.8a 28=1.8a a=15.5m/s2

What is the acceleration of the car between 20 and 50 sec?

the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory): s = ut + Β½at^2 …. (1) v^2 = u^2 + 2as …. (2) v = u + at …. (3) s = (u + v)t/2 …. (4) where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time. In this case, we know u = 10m/s, v = 50m/s, t = 10s and we want to find a, so we use equation (3) v = u + at 50 = 10 + 10t, so t = (50 – 10)/10 = 4m/s^2

Are you able to divide 3 fractions instead of 2?

Yes. a/b / u/v / r/s = (a*v)/(b*u) / r/s = (a * v * s) / (b * u * r)

A car traveling at a velocity of 24 m s is accelerated uniformly at a rate of 2 m s for 8 seconds what is the final velocity of the car?

Apply to the equation V=U+at . The answer is 40.

What are the three formulas used in Uniformly Accelerated Motion?

The SUVAT equations: s=ut + 1/2at^2 v= u + at v^2 = u^2 + 2as s=1/2(u+v)t s = displacement u= initial velocity v= final velocity a= acceleration t= time

If a egg is dropped from eleven meters how fast will it be going?

The speed at which the egg will be traveling when it hits the ground depends on various factors such as air resistance and initial velocity. Assuming the egg is in free fall and neglecting air resistance, its speed when it hits the ground can be calculated using the equation (v = \sqrt{2 \cdot g \cdot h}), where (v) is the final velocity, (g) is the acceleration due to gravity (approximately 9.81 m/sΒ²), and (h) is the height (11 meters in this case). This would give a final velocity of approximately 14 m/s.

Third equation of motion?

v2- u 2 = 2assince, S (Distance) = Average speed x TimeS = U+V / 2 * TS = U+V / 2 * V - U / A {since T = V -U / A}S = V2 - U2 / 2A2AS = V2 - U2OR V2 - U2 = AsHence, Derived.

What is the spelling of survive?

It is spelled s-u-r-v-i-v-e.

Equation for acceleration?

acceleration(a) = (final velocity(v) - Initial velocity(u)) / time (s) Algebraically a = (v - u) / t Where 'v' & 'u' are measured in metres per second ( m/s) or ms^-1 And 't' is the time in seconds measured is 's' Hence a(ms^-2) = v(m/s) - u(m/s)) / t(s) And example is a car starting from rest up to 44 m/s ( 30 mph) in 10 seconds. a = (44 - 0 ) / 10 a = 44/10 a = 4.4 ms^-2. NB Earth's gravitational acceleration(g) is approximately 10 ms^-2.

How do you use the LCM to write fractions with a common denominator?

Suppose you have the fractions p/q and r/s. Let the LCM of q and s be t.Then t is a multiple of q as well as of s so let t= q*u and t = s*v Then p/q = (p*u)/(q*u) = (p*u)/t and r/s = (r*v)/(s*v) = (r*v)/t have the same denominators.

A bike starts at rest and after 5s it is moving at 5mk what is the average acceleration?

v = u + at where u = starting velocity, v = final velocity, a = acceleration, t = time. Here u = 0 so v = at ie a = v/t Now, v = 5 m/s (what is mk?) and t = 5 s So a = (5 m/s) / 5 s = 1 m/s2