The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.
First, we can use the distance formula to find the length of LM: d(L,M) = sqrt((4 - (-3))^2 + (9 - 1)^2) = sqrt(49 + 64) = sqrt(113) Since LM:MN = 2:3, we can express the distance from L to N as (3/2) times the distance from L to M: d(L,N) = (3/2) * d(L,M) = (3/2) * sqrt(113) To find the coordinates of N, we need to determine the direction from M to N. We know that LMN is a straight line, so the direction from M to N is the same as the direction from L to M. We can find this direction by subtracting the coordinates of L from the coordinates of M: direction = (4 - (-3), 9 - 1) = (7, 8) To find the coordinates of N, we start at M and move in the direction of LMN for a distance of (3/2) * d(L,M): N = M + (3/2) * d(L,M) * direction / ||direction|| where ||direction|| is the length of the direction vector, which is: ||direction|| = sqrt(7^2 + 8^2) = sqrt(113) Substituting the values, we get: N = (4, 9) + (3/2) * sqrt(113) * (7/sqrt(113), 8/sqrt(113)) Simplifying, we get: N = (4 + (21/2), 9 + (24/2)) = (14.5, 21) Therefore, the coordinates of N are (14.5, 21). Answered by ChatGPT 3
London
E N G L A N D
P Park R Reverse N Neutral D Drive 2 Second gear L Low gear
In a sequence of numbers, a(1), a(2), a(3), ... , a(n), a(n+1), ... he first differences are a(2) - a(1), a(3) - a(2), ... , a(n+1) - a(n) , ... Alternatively, d the sequence of first differences is given by d(n) = a(n+1) - a(n), n = 1, 2, 3, ...
A 3s electron
1 q 1 d 1 q 2 n 2 d 3 n 3 d 1 n 1 d 5 n 7 n
There are 22 ways to make change from a dollar using nickels, dimes, and quarters. 1. 4 q 2. 10 d 3. 20 n 4. 2 q , 5 d 5. 3 q , 2 d , 1 n 6. 1 q , 7 d, 1 n 7. 9 d, 2 n 8. 8 d, 4 n 9. 7 d, 6 n 10. 6 d , 8 n 11. 5 d , 10 n 12. 4 d , 12 n 13. 2 d , 16 n 14. 1 d , 18 n 15. 5 n , 3 q 16. 3 n , 1 q , 6 d 17. 7 n , 1 q , 4 d 18. 9 n , 1 q , 3 d 19. 11 n , 1 q , 2 d 20. 13 n , 1 q , 1 d 21. 14n , 3 d 22. 15n , 1 q
Given an arithmetic sequence whose first term is a, last term is l and common difference is d is:The series of partial sums, Sn, is given bySn = 1/2*n*(a + l) = 1/2*n*[2a + (n-1)*d]
You will need to define the input and times length by width.For example: L - Length & W - Widthstartsum = 0input L, Wsum = L * Wprint "The area of the rectangle is: SUM"end
No, because is n=1, the electron is in the first energy level, therefore cannot have a l=2, because l= n-1. Or more simply put l=2 is a d-orbital, and there are no d-orbitals in the first energy level. ml=0 is correct because ml= +-l through 0.