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Well, I'm no math expert, but I believe that if one car was to hold a specific lane, the possible combinations would be six per lane. If we multiply that by four lanes, the outcome should be 24 possible combinations. Here is the list of possible outcomes:

1234, 1243, 1324, 1342, 1423, 1432, 2134, 2143, 2314, 2341, 2413, 2431, 3124, 3142, 3214, 3241, 3412, 3421, 4123, 4132, 4213, 4231, 4312, 4321.

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Q: There are four cars entered into a pinewood derby race In how many different orders can they cross the finish line?
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