Well, I'm no math expert, but I believe that if one car was to hold a specific lane, the possible combinations would be six per lane. If we multiply that by four lanes, the outcome should be 24 possible combinations. Here is the list of possible outcomes:
1234, 1243, 1324, 1342, 1423, 1432, 2134, 2143, 2314, 2341, 2413, 2431, 3124, 3142, 3214, 3241, 3412, 3421, 4123, 4132, 4213, 4231, 4312, 4321.
Six runners can finish in 36 different orders in a race. This sum is reached by multiplying the number of runners (6), by the number of runners (6).
There are 720 possible orders in which 6 horses can finish a race.
6 permute 6 =720 ways :))
no they can not
You do 5! 5 x 4 x 3 x 2 x 1 The answer is : 120
simple... there are two orders: the natural order and the inverted order.
An example of two organisms in the same class but different orders is a lion (order: Carnivora) and a horse (order: Perissodactyla). Both belong to the class Mammalia, but they are classified under different orders based on their biological characteristics and evolutionary history.
The arrangement of objects in different orders.
to keep physicians from over-medicating patients
Rodents
Not really, although there are different orders of infinity.
Anagram. :)