I don't know if it does, but assuming it does, it's because the bullet is travelling so fast. I believe momentum is figured by multiplying the mass of the object by the speed. A truck is much larger, but moving much slower, so it's possible the figures are close. However, the end result would be different. The effect of a bullet hitting a person is MUCH different than the effect of a truck hitting a person. Contrary to popular myth, bullets don't knock people down (and yes, I know that for a fact, because I have seen people get shot), and they certainly don't propel the persons body anywhere, however, if you got hit by a 10,000 pound truck going 70 MPH, I'm quite sure that would propel your body some distance.
A parked semi truck has no momentum. A moving bicycle does. If both the bike and the truck are moving at the same speed in the same direction, the truck will have more because it has more mass.
The truck has the most mass, but because it is at rest, the skateboard has the most momentum.
By traveling at the same speed. Kinetic energy is a completely different story, however.
Momentum = Ρ = m•v, m is mass in kg, and v is velocity in m/s. Both the semi and the linebacker are traveling at the same velocity. However, the mass of the semi is hundreds of times the mass of the linebacker. Therefore, the semi will have a much greater momentum than the linebacker.
More force would be needed to stop a semi truck than a motorcycle. This is because a semi truck is heavier and has more momentum, requiring more force to slow down or stop.
Yes.
Who invented the Semi-truck?
If the semi truck knocked on the garbage truck, yes.
A vehicle with 18 wheels is commonly known as a "semi-truck" or "tractor-trailer."
Semi-articulated
The Toyota would have more acceleration a= F/m if the mass of the of the Semi Truck is greater than the mass of the Toyota.
Purchasing insurance for a semi truck requires the same information as that of car insurance. The age of the driver, the drivers driving history, the age and make of the truck and the value of the load.