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A race car starts from rest and accelerates uniformly of 40ms in 8 seconds. How far will the car travel during the 8 seconds?
The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.
A rave car starts from rest and accelerates uniformly to a speed of 40 ms in 8.0 seconds. How far will the car travel during the 8 seconds?
The distance the car travels during the acceleration can be calculated using the formula: distance = (initial velocity)(time) + 0.5(acceleration)(time)^2. Plug in the values: initial velocity = 0 m/s, final velocity = 40 m/s, time = 8 s. Calculate the distance traveled during the acceleration.
What is the final velocity of an object that starts from rest and accelerates uniformly with an acceleration of 2 m/s2 over a distance of 2 meters?
The final velocity of the object is 4 m/s.
How many meters does a car travel that starts from rest and accelerates for 4.7 seconds with an acceleration rate of 3.6 meters per second squared?
60.912 meters in that time
Sydney has a car that accelerates at 5.9ms squared. She was races Sean. Both start from rest but Sean starts 1.0 seconds early. Seans car accelerates at 3.6ms squared.?
Sydney's car accelerates at 5.9 m/s^2, while Sean's car accelerates at 3.6 m/s^2. Sean starting 1.0 second early gives him an initial distance advantage, but Sydney's higher acceleration rate means she will catch up and overtake Sean at some point during the race. The exact point of overtaking can be calculated by comparing their positions over time.
A car accelerates from rest at 2 meters per second per second What is its speed 3 seconds after the car starts moving?
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
Would you Give me a question and answer about acceleration?
Question:A car starts from rest and accelerates uniformly. It acquires a velocity of 72 km/hr in 10 seconds. What is its acceleration?Answer:Since the car is starting fom rest, its initial velcity (u) = 0Final velocity (v) = 72 km/hr =20 m/sTime taken for change of velocity (t) = 10 secondsAcceleration, a = (v-u)/t = (20-0)/10 = 20/10 = 2 m/s2
What is the velocity of an object that starts at 45 mph and accelerates at a rate of -10 mphsec for 3 seconds?
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
When does summer salmon starts in Washington?
Fishing tends to start out slow, then accelerates quickly through the month of August.
How does your weight mass and the normal force exerted by the floor change when you are in an elevator that starts from rest and accelerates upward?
When you are in an elevator that starts from rest and accelerates upward, your weight (mass times gravitational acceleration) remains constant because your mass does not change. However, the normal force exerted by the floor increases during the upward acceleration. This is because the elevator's acceleration adds to the gravitational force, resulting in a greater normal force acting on you, which can be felt as an increase in apparent weight.
Time that's starts with s?
seconds
How far does a car travel when it starts from rest and accelerates to a certain speed?
The distance a car travels when it starts from rest and accelerates to a certain speed depends on the acceleration of the car and the time it takes to reach that speed. The formula to calculate this distance is d 0.5 a t2, where d is the distance, a is the acceleration, and t is the time taken to reach the speed.
